All categories

3 years ago

¿Cuál es el valor de la sumatoria de todas las fuerzas que actúan sobre un cuerpo que está en equilibrio?

Physics

1 answer:

VLD [36.1K]3 years ago

8 0

Answer:

Zero

Explanation:

The addition of all forces acting on a body which is in equilibrium must be zero, since there must'n be any acceleration (net acting force must be zero)

You might be interested in

H<br>Ggghffyjfdudjhfhghggffghjjdxv

amid [387]

Answer:

Ggghffyjfdudjhfhghggffghjjdxv

Explanation: The law of copying

6 0

3 years ago

Which statement best describes the relationship between atoms and nuclear forces? (2 points)

Setler79 [48]

Answer:

D. Strong nuclear forces hold the nucleus of an atom together. Weak nuclear forces are involved when certain types of atoms break down.

Explanation:

4 0

2 years ago

A child dangles a 1.50-kilogram stuffed toy 0.500 meters from the ground. What is the potential energy of the toy?

inn [45]

Since we know that
Gravitational potential energy = mass × height ×gravity

then

GPE = 1.5 kg x 0.500 m x 9.8m/s^2

therefore

GPE = 7.35 J

6 0

3 years ago

Read 2 more answers

PLEASE HELP ME ANSWER DUE SOON BRAINLIEST FOR WHOEVER

DerKrebs [107]

Answer:

1) mechanical

2) transverse

3) medium

4) longitudinal

Explanation:

7 0

3 years ago

A 280-m-wide river flows due east at a uniform speed of 4.7m/s. A boat with a speed of 7.1m/s relative to the water leaves the s

tamaranim1 [39]

Answer:

(a) The speed is 7.96 m/s

(b) The direction is 76 degree from positive X axis in counter clockwise direction.

Explanation:

Width of river = 280 m

speed of river, vR = 4.7 m/s towards east

speed of boat with respect to water, v(B,R) = 7.1 m/s at 26 degree west of north

$vR = 4.7 i \\\\v(B,R) = 7.1 (- sin 26 i + cos 26 j) = - 3.1 i + 6.4 j$

(a) The velocity of boat with respect to ground is

$\overrightarrow{v}_{(B,R)}=\overrightarrow{v}_{(B,G)}-\overrightarrow{v}_{(R,G)}\\\\- 3.1 \widehat{i} +6.4 \widehat{j}=\overrightarrow{v}_{(B,G)} - 4.7 \widehat{i}\\\\\overrightarrow{v}_{(B,G)} = 1.6 \widehat{i} + 6.4 \widehat{j}\\\\{v}_{(B,G)} = \sqrt{1.6^2 + 6.4^2}=6.96 m/s$

(b) The direction is given by

$tan\theta = \frac{6.4}{1.6} =4\\\\\theta = 76^o$

7 0

3 years ago