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irina [24]
2 years ago
12

¿Cuál es el valor de la sumatoria de todas las fuerzas que actúan sobre un cuerpo que está en equilibrio?

Physics
1 answer:
VLD [36.1K]2 years ago
8 0

Answer:

Zero

Explanation:

The addition of all forces acting on a body which is in equilibrium must be zero, since there must'n be any acceleration (net acting force must be zero)

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I de momento que no what now what the que no se puede el gobierno del presidente y el gobierno
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How much force is needed to accelerate a 2500 kg car at a rate of 3.5 m/s^2?
Sati [7]

F = ma  

F = applied force in newtons = to be determined  

m = mass of the car = 2,500 kg  

a = acceleration of the car = 3.5 m/s²  

F = (2,500 kg)(3.5 m/s²)  

F =8750

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What happens when an ionic compound is melted?
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It conducts electricity. This is because the electrons are able to move around more for it has gained energy, after being heated.
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How much heat energy is produced by 0.5 Wh of electrical energy ?
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1.7 Btu

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1watt * 1h = 3.41214 Btu/h * h

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Read 2 more answers
A baseball pitcher throws the ball towards the batter at 90 mph. His bat connects with the ball for a line drive, after which th
forsale [732]

Answer:

F=-18412.9N, where the minus indicates the direction is opposite to that of the throw.

Explanation:

a)

Since MKS stands for meter-kilogram-second and we know that:

1\ hour = 3600\ seconds

1\ mile = 1600\ meters

1000g = 1kg

We can write that:

\frac{1\ hour}{3600\ seconds}=1

\frac{1600\ meters}{1\ mile}=1

\frac{1kg}{1000g}=1

These are conversion factors, equal to 1, so multiplying our results by them won't change their value, only their units.

So we have that:

90 mph=90 \frac{miles}{hour}(\frac{1\ hour}{3600\ seconds})(\frac{1600\ meters}{1\ mile})=40m/s

110 mph=110 \frac{miles}{hour}(\frac{1\ hour}{3600\ seconds})(\frac{1600\ meters}{1\ mile})=48.89m/s

145 g=145 g(\frac{1kg}{1000g})=0.145kg

b)

Newton's 2nd Law tells us that F=ma, and the definition of acceleration is a=\frac{\Delta v}{\Delta t}, so we have:

F=m\frac{\Delta v}{\Delta t}=m\frac{v_f-v_i}{t}

Taking the throw direction as the positive one, for our values we have:

F=m\frac{v_f-v_i}{t}=(0.145kg)\frac{(-48.89m/s)-(+40m/s)}{0.0007s}=-18412.9N

4 0
3 years ago
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