Ah for this problem you are thinking quite a bit hard on. The problem is actually simpler than it looks. The problem states that a bike travels at a constant speed of 3.1 m/s for 6 s and asks how far will it go?. To figure this out you simply need to take 3.1 times 6 s because every second the bike travels 3.1 m. So the answer to this problem would be 18.6 m
Answer:
The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.
Explanation:
Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.
Answer:
Perfume is a mixture of fragrant oils in an ethanol/water solvent. The ethanol/water mixture, which is volatile, evaporates from the droplets within a few seconds, leaving behind a droplet of the fragrant compounds in the perfume. These compounds will also eventually evaporate to form a vapor of the fragrant molecules
Answer:
The rock has an impact speed of 9.9 m/s.
Explanation:
given information:
object's mass, m = 3 kg
height, h = 5 m
in this case, the potential energy is equal to the kinetic energy
PE = KE
mgh = 
mv²
where
m = mass (kg)
g = gravitational constant (9.8 m/s²)
v = velocity (m/s)
so,
mgh = mv²
gh = v²
v² = 2gh
v = √2gh
= √(2)(9.8)(5)
= 9.9 m/s
