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mojhsa [17]
1 year ago
7

A sample of nitrogen gas has a volume of 5.0 ml at a pressure of 1.50 atm. what is the pressure exerted by the gas if the volume

increases to 30.0 ml, at constant temperature?
Physics
1 answer:
olchik [2.2K]1 year ago
8 0

A sample of nitrogen gas has a volume of 5.0 ml at a pressure of 1.50 atm. what is the pressure exerted by the gas if the volume increases to 30.0 ml, at constant temperature is 0.25atm.

On constant temperature, the pressure and volume relation become constant before and after the change in quantitities have occurred.

According to Boyle's Law,

P₁V₁ = P₂V₂

where, P₁ is pressure exerted by the gas initially

V₁ is the volume of gas initially

P₂ is pressure exerted by the gas finally

V₂ is the volume of gas finally

Given,

P₁ = 1.5 atm

V₁ = 5 ml

V₂ = 30 ml

P₂ =?

On substituting the given values in the above equation:

P₁V₁ = P₂V₂

1.5 atm × 5 ml = P₂ × 30 ml

P₂ = 0.25 atm

Hence, pressure exerted by the gas is 0.25atm.

Learn more about Boyle's Law here, brainly.com/question/1437490

#SPJ4

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Answer:

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a uniform beam of length l and mass mb is supported by two pillars located l/3 from either end, as shown in the figure. a duck o
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When the system is in equilibrium, the sum of the moment about a point is

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Force \ shown  \ by \  the  \ scale \  under \  the \  right  \ pillar \ is \ F = \dfrac{(m_B - 2 \cdot m_D) \cdot g}{2}

Reasons:

Length of the beam = l

Mass of the beam = m_B

Location \ of \  the \  two \  pillars = \dfrac{l}{3}  \  from  \  either  \  end

Mass of the duck = m_D

Required:

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Solution:

The location of the duck = On the left end of the beam

When the system is in equilibrium, we have; ∑M = 0

Taking moment about the left pillar, we get;

Clockwise moment = m_D \times g \times  \dfrac{l}{3} + F \times \dfrac{l}{3}

Anticlockwise moment = m_B \times g \times  \dfrac{l}{6}

At equilibrium, clockwise moment = Anticlockwise moment

Therefore;

m_D \times g \times  \dfrac{l}{3} + F \times \dfrac{l}{3} = m_B \times g \times  \dfrac{l}{6}

F \times \dfrac{l}{3} = m_B \times g \times  \dfrac{l}{6} - m_D \times g \times  \dfrac{l}{3}

F = \dfrac{m_B \times g \times  \dfrac{l}{6} - m_D \times g \times  \dfrac{l}{3}}{\dfrac{l}{3} }  = \dfrac{(m_B - 2 \cdot m_D) \cdot g}{2}

Force \ shown  \ by \  the  \ scale \  under \  the \  right  \ pillar, \  F = \dfrac{(m_B - 2 \cdot m_D) \cdot g}{2}

Learn more here:

brainly.com/question/12227548

brainly.com/question/14778371

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A diver with a mass of 80.0 kg jumps from a dock into a 130.0 kg boat at rest on the west side of the dock. if the velocity of t
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Applying conservation of momentum;

m_{1}  v_{1} + m_{2}  v_{2} = m_{f}  v_{f}

Where m1 = 80.0 kg; v1 =4.10 m/s; m2 = 130.0 kg; v2 = 0; mf = (80+130) kg; vf = ??

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Which type of image is formed by convex lens on a screen?​
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Answer:

The type of image formed on a screen by a convex lens is real, enlarged and inverted.

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A lens can be defined as a transparent optical instrument that refracts rays of light to produce a real image.

Basically, there are two (2) main types of lens and these includes;

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II. Converging (convex) lens.

A converging lens refers to a type of lens that typically causes parallel rays of light with respect to its principal axis to come to a focus (converge) and form a real image.

Basically, the type of image formed on a screen by a converging (convex) lens is real, enlarged and inverted because it is usually thick across the middle (causing rays of light to converge) but thin at the lower and upper edges.

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Explanation:

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