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sasho [114]
3 years ago
5

Science Write two examples of heating appliances

Physics
1 answer:
bearhunter [10]3 years ago
4 0

Answer:

a} <u>Infrared radiant heaters.</u>

<u>b} Fan heaters.</u>

Explanation:

I hope this is okay, should I give more.

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Tony has a mass of 50 kg, and his friend Sam has a mass of 45 kg. Assume that both friends push off on their rollerblades with t
Citrus2011 [14]

Answer:

Sam

Explanation:

Hes lighter

3 0
3 years ago
What is the average speed of a car that travels 60 meters in 2<br> seconds?
blondinia [14]

Answer:

30 m/s

Explanation:

Speed is distance over time. 60 meters / 2 seconds, = 30 m/s.

6 0
3 years ago
Assume that the loop is initially positioned at θ=30∘θ=30∘ and the current flowing into the loop is 0.500 AA . If the magnitude
labwork [276]

Answer:\tau=1.03\times 10^{-4}\ N-m

Torque,

Explanation:

Given that,

The loop is positioned at an angle of 30 degrees.

Current in the loop, I = 0.5 A

The magnitude of the magnetic field is 0.300 T, B = 0.3 T

We need to find the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field. We know that the torque is given by :

\tau=NIAB\ \sin\theta

Let us assume that, A=0.0008\ m^2

\theta is the angle between normal and the magnetic field, \theta=90^{\circ}-30^{\circ}=60^{\circ}

Torque is given by :

\tau=1\times 0.5\ A\times 0.0008\ m^2\times 0.3\ T\ \sin(60)\\\\\tau=1.03\times 10^{-4}\ N-m

So, the net torque about the vertical axis is 1.03\times 10^{-4}\ N-m. Hence, this is the required solution.

4 0
2 years ago
A moving roller coaster speeds up with constant acceleration for 2.3\,\text{s}2.3s2, point, 3, start text, s, end text until it
Ad libitum [116K]

Answer:

Δx=(v+v0/2)t

Explanation:

We can figure out which kinematic formula to use by choosing the formula that includes the known variables, plus the target unknown.

In this problem, the target unknown is the initial velocity v_0v  

0

​  

v, start subscript, 0, end subscript of the roller coaster.

7 0
3 years ago
At what position in its elliptical orbit is the speed of a planet a maximum? when it is closest to the sun when it is farthest f
Phantasy [73]

Answer:

1.when it is closest to the sun

2.when it is midway between its farthest

Explanation:

According to the law of  Kepler's

T ² ∝ r³

T=Time period

r=semi major axis

We also know that time period T given as

T=\dfrac{2\pi r}{v}

v=Speed

v=\dfrac{2\pi r}{T}

v\alpha \dfrac{r}{T}

v\alpha \dfrac{r}{T}

v^2\alpha \dfrac{r^2}{T^2}

v^2\alpha \dfrac{r^2}{r^3}

v^2\alpha \dfrac{1}{r}

v\alpha \dfrac{1}{\sqrt{r}}

So we can say that ,when r is more then the speed will be minimum and when r is low then speed will be maximum.

7 0
3 years ago
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