Answer:
W = 55.12 J
Explanation:
Given,
Natural length = 6 in
Force = 4 lb, stretched length = 8.4 in
We know,
F = k x
k is spring constant
4 = k (8.4-6)
k = 1.67 lb/in
Work done to stretch the spring to 10.1 in.
W = 55.12 J
Work done in stretching spring from 6 in to 10.1 in is equal to 55.12 J.
Answer:
<em>The third piece moves at 6.36 m/s at an angle of 65° below the horizon</em>
Explanation:
Linear Momentum
It's a physical magnitude that measures the product of the velocity by the mass of a moving object. In a system where no external forces are acting, the total momentum remains unchanged regardless of the interactions between the objects in the system.
If the velocity of an object of mass m is , the linear momentum is computed by
a)
The momentum of the board before the explosion is
Since the board was initially at rest
After the explosion, 3 pieces are propelled in different directions and velocities, and the total momentum is
The first piece of 2 kg moves at 10 m/s in a 60° direction
We find the components of that velocity
The second piece of 1.2 kg goes at 15 m/s in a 180° direction
Its components are computed
The total momentum becomes
Operating
Knowing the total momentum equals the initial momentum
Rearranging
Calculating
This is the momentum of the third piece
b)
From the above equation, we solve for :
The magnitude of the velocity is
And the angle is
The third piece moves at 6.36 m/s at an angle of 65° below the horizon