This the answer to the question you asked:)
Answer:
Explanation:
250 cm^3 of 0.2 moldm-3 H2SO4 can be prepared from 150cm^3 of 1.0 moldm^-3 by dilution.
150cm^3 of the 1.0 moldm^-3 stock solution is measured out using a measuring cylinder and transferred into a 250 cm^3 standard volumetric flask and made up to mark. The resulting solution is now 250cm^3 of 0.2 moldm-3 H2SO4.
1 molecule of NaCl contains 1 sodium ion (Na+), that's why if we have 3.0 moles of.
NaCl, we have 3.0 moles of Na+.
N(ions) = n(mol) · NA.
N(ions) = 3.0 moles · 6.02·1023 = 18.06 ·1023 ions.
When you transferred the hot metal from the boiling water and into the calorimeter, The effect will be
- Change in temp is positive
- Temp of metal V, dT=-ve
- No change occurs in the specific heat of metal
This is further explained below.
<h3>What is the Specific heat of the metal?</h3>
a )Since the metal of the cup is hot and the water inside is cold, the water's temperature will rise as heat is transferred from the metal to the liquid.
Change in temp is positive
b)
Due to (a), heat is lost from the food to the water in the cup, lowering the metal's temperature.
Temp of metal V, dT=-ve
c)
No change occurs in the specific heat of metal because of its constant property.
Read more about Temperature
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