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Gnoma [55]
3 years ago
12

A worker is told her chances of being killed by a particular process are 1 in every 300 years. Should the worker be satisfied or

alarmed? What is the FAR (assuming normal working hours) and the deaths per person per year? What should her chances be, assuming an average chemical plant?
Chemistry
1 answer:
Pavlova-9 [17]3 years ago
4 0

Answer:

(a) Yes, he should be worried. The Fatal accident rate (FAR) is too high according to standars of the industry. This chemical plant has a FAR of 167, where in average chemical plants the FAR is about 4.

(b) FAR=167 and Death poer person per year = 0.0033 deaths/year.

(c) The expected number of fatalities on a average chemical plant are one in 12500 years.

Explanation:

Asumming 50 weeks of work, with 40 hours/week, we have 2000 work hours a year.

In 300 years we have 600,000 hours.

With these estimations, we have (1/600,000)=1.67*10^(-6) deaths/hour.

If we have 2000 work hours a year, it is expected 0.0033 deaths/year.

1.67*10^{-6} \frac{deaths}{hour}*2000 \frac{hours}{year}=0.0033 deaths/year

The Fatal accident rate (FAR) can be expressed as the expected number of fatalities in 100 millions hours (10^(8) hours).

In these case we have calculated 1.67*10^(-6) deaths/hour, so we can estimate FAR as:

FAR=1.67*10^{-6} \frac{deaths}{hour}*10^{8}  hours=1.67*10^{2} =167

A FAR of 167 is very high compared to the typical chemical plants (FAR=4), so the worker has reasons to be worried.

If we assume FAR=4, as in an average chemical plant, we expect

4\frac{deaths}{10^{8} hour} *2000\frac{hours}{year}=8*10^{-5} \frac{deaths}{year}

This is equivalent to say

\frac{1}{8*10^{-5} } \frac{years}{death}=1.25*10^{4} \frac{years}{death} =12500 \, \frac{years}{death}

The expected number of fatalities on a average chemical plant are one in 12500 years.

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Answer:

The answer to your question is 27 g of Al

Explanation:

Data

mass of Al = ?

moles of Al₂O₃ = 0.5

The correct formula for the product is Al₂O₃

Balanced chemical reaction

               4Al + 3O₂   ⇒   2Al₂O₃

Process

1.- Calculate the molar mass of the product

Al₂O₃ = (27 x 2) + (16 x 3)

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         = 102 g

2.- Convert the moles of Al₂O₃ to grams

               102 g ---------------- 1 mol

                 x       ----------------  0.5 moles

                 x = (0.5 x 102) / 1

                 x = 51 g of Al₂O₃

3.- Use proportions to calculate the mass of Al

                4(27) g of Al --------------- 2(102) g of Al₂O₃

                     x               --------------- 51 g

                        x = (51 x 4(27)) / 2(102)

                        x = 5508 / 204

                        x = 27 g of Al

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