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Answer:
Explanation:
CH₃Br+NaOH⟶CH₃OH+NaBr
It is a single step bimolecular reaction so order of reaction is 2 , one for CH₃Br and one for NaOH .
rate of reaction = k x [CH₃Br] [ NaOH]
.008 = k x .12 x .12
k = .55555
when concentration of CH₃Br is doubled
rate of reaction = .555555 x [.24] [ .12 ]
= .016 M/s
when concentration of NaOH is halved
rate of reaction = .555555 x [.12] [ .06 ]
= .004 M/s
when concentration of both CH₃Br and Na OH is made 5 times
rate of reaction = .555555 x .6 x .6
= 0.2 M/s
Answer:
Mass = 427.05 g
Explanation:
Given data:
Formula units of sodium chloride = 4.38 ×10²⁴
Mass of NaCl = ?
Solution:
One mole contain formula units = 6.022 ×10²³
4.38×10²⁴ formula units × 1mol /6.022 ×10²³ formula units
0.73 ×10¹ mol
7.3 mol
Mass of NaCl:
Mass = number of moles × molar mass
Mass = 7.3 mol × 58.5 g/mol
Mass = 427.05 g
Answer:
The volume of the solution is 133 ml
Explanation:
Having a 0.250 molar solution means 0.250 moles in 1000 ml of solution (1 liter)
We calculate the weight of 1 mole of CuNO3, and use 3 simple rules for calculations:
CuNo3---> Weight of 1 mole= 63, 546g+ 14, 0067g+ 3X 15, 9999g= 125, 55g/mol
1 mol----125, 55g
0,250mol---X= (0,250molx 125,55g)/1mol= 31,3 g
31,3g----1000ml
4,16g---x= (4,16gx1000ml)/31,3g = 133ml