Answer:
607 ppm
Explanation:
In this case we can start with the <u>ppm formula</u>:
If we have a solution of <u>0.0320 M</u>, we can say that in 1 L we have 0.032 mol of 
, because the molarity formula is:
In other words:
If we use the <u>atomic mass</u> of 
(19 g/mol) we can convert from mol to g:
Now we can <u>convert from g to mg</u> (1 g= 1000 mg), so:
Finally we can <u>divide by 1 L</u> to find the ppm:
<u>We will have a concentration of 607 ppm.</u>
I hope it helps!
13.4 billion years is 3 times of the half-life, 4.47 billion years. So the Uranium-238 will go through three times of half decay. So the remain percentage will be 50%*50%*50%=12.5%.
Answer:
1.40*10⁻² M
Explanation:
We have the solubility formula
Solubility,
S = KH*P
where
KH = measure of hardness of water / carbonate hardness = 3.50*10⁻² mol/L.atm
P = atmospheric pressure = 0.400 atm
Hence, we have
S = KH*P
= (3.50*10⁻² mol/L.atm)*(0.400 atm)
= 1.40*10⁻² mol/L
But 1 mol/L = 1 M,
Hence, the answer (1.40*10⁻² mol/L
) is equivalent to
= 1.40*10⁻² M
For the first one it’s 69 just count the little lines from the side.
[Ar] 3d10 4s2 4p5 is the electron configuration of bromine
