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3 years ago

A gas occupied 23.55 L at 118.2 Celsius. At what temp would the gas occupied 43.8 L

Chemistry

1 answer:

pantera1 [17]3 years ago

4 0

Answer:

The gas occupies 43.8 L at a temperature of 219.8 °C

Explanation:

<u>Step 1:</u> Data given

Volume of the gas = 23.55L

Temperature = 118.2 °C

New volume = 43.8 L

<u>Step 2</u>: Calculate changed temperature

(P1*V1)/T1 = (P2*V2)/T2

Let's assume the pressure stays constant, then we have:

V1/T1 = V2/T2

⇒ with V1 = the initial volume = 23.55L

⇒ with T1 = the initial temperature = 118.2 °C

⇒ with V2 = the changed volume = 43.8 L

⇒ with T2 = the changed temperature = TO BE DETERMINED

23.55L/118.2°C = 43.8 L / T2

T2 = 219.8 °C

The gas occupies 43.8 L at a temperature of 219.8 °C

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$\huge{ \underline{ \boxed{ \bf{ \green{Answer:}}}}}$

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