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raketka [301]
2 years ago
13

In Part C, how would the effects differ if you connected the galvanometer to the primary coil and the battery/switch to the seco

ndary
Physics
1 answer:
Katen [24]2 years ago
4 0

N₂ / N₁ = 13.3

A transformer is a device that changes the voltage in the primary, causing a voltage to be induced in the secondary. The expression for this voltage ratio is

ΔV₂ = N₂ /N₁ ΔV₁

where N is the number of windings on each side and V2 and V1 are the voltages in the secondary and primary, respectively.

They state that the primary voltage in this instance is 9.0 V and the secondary voltage is 120 V.

ΔV₂ /ΔV₁ = N₂ / N₁

N₂ / N₁ = 120/9

N₂ / N₁ = 13.3

Learn more about  voltage here brainly.com/question/16774947

#SPJ4.

A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secondary coil is connected to a light bulb that operates on 120 V. Determine the ratio of the secondary to primary turns needed for the bell's transformer. Determine the ratio of the secondary to primary turns needed for the bells transformer. Ns/Np=?

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igor_vitrenko [27]
  • Mass=2kg
  • Velocity=40m/s

We know

\boxed{\sf K.E=\dfrac{1}{2}mv^2}

  • m denotes to mass
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\\ \sf\longmapsto K.E=\dfrac{1}{2}\times 2\times 40^2

\\ \sf\longmapsto K.E=40^2

\\ \sf\longmapsto K.E=1600J

6 0
3 years ago
A racquet ball with mass m = 0.256 kg is moving toward the wall at v = 11.8 m/s and at an angle of θ = 29° with respect to the h
icang [17]

Answer:

Part a)

P = 5.72 kg m/s

Part b)

\Delta P = 2.93 kg m/s

Part c)

F = 44.4 N

Part d)

\Delta P = 5.02 kg m/s

Part e)

\Delta t = 0.113 s

Part f)

\Delta K = 0

Explanation:

As we know that initial velocity of the ball is given as

v = 11.8 cos29 \hat i + 11.8 sin29 \hat j

v_i = 10.3 \hat i + 5.72 \hat j

Now final velocity of the system is given as

v_f = 10.3\hat i - 5.72\hat j

Part a)

now magnitude of initial momentum is given as

P = mv

P = 0.256(11.8)

P = 5.72 kg m/s

Part b)

Change in momentum is given as

\Delta P = m(v_f - v_i)

\Delta P = 0.256(5.72 + 5.72)

\Delta P = 2.93 kg m/s

Part c)

As we know that average force is defined as the rate of change in momentum

so here we have

F = \frac{\Delta P}{\Delta t}

F = \frac{2.93}{0.066}

F = 44.4 N

Part d)

Magnitude of change in momentum is given as

\Delta P = m(v_f - v_i)

\Delta P = 0.256(7.8 + 11.8)

\Delta P = 5.02 kg m/s

Part e)

As we know that in 2nd case the force is same as the initial force

so we will have

\frac{\Delta P}{\Delta t} = F

\frac{5.02}{\Delta t} = 44.4

\Delta t = 0.113 s

Part f)

Since this is elastic collision so change in kinetic energy must be ZERO

\Delta K = 0

8 0
3 years ago
A spring has a force constant k, and an object of mass m is suspended from it. The spring is cut in half and the same object is
kenny6666 [7]

Answer:

f2/f1 = \sqrt{2}

Explanation:

From frequency of oscillation

f = 1/2pi *\sqrt{k/m}

Initially with the suspended string, the above equation is correct for the relation, hence

f1 = 1/2pi *\sqrt{k/m}

where k is force constant and m is the mass

When the spring is cut into half, by physics, the force constant will be doubled as they are inversely proportional

f2 = 1/2pi *\sqrt{2k/m}

Employing f2/ f1, we have

f2/f1 = \sqrt{2}

3 0
3 years ago
Which best describes the definition for the atomic mass of an element?
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7 0
3 years ago
At what time will the interfering waves have an amplitude of zero
stepladder [879]

When the interfering waves have an amplitude of zero the phenomena is called destructive interference.

It occurs when waves come together in such a way that they completely cancel each other out. When two waves interfere destructively, they must have the same amplitude in opposite directions it means that the waves are in 180° different phase from each other.

4 0
3 years ago
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