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viktelen [127]
3 years ago
11

WILL GIVE BRAINLIEST!!!

Physics
1 answer:
vovikov84 [41]3 years ago
3 0

Answer:

D.

boulder-sized rocks that come from the asteroid belt

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Specific heat is the amount of heat required to raise the temperature of a material by 1°C per what unit?
nydimaria [60]

The heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).


or C. Mass if you're on plato

3 0
3 years ago
Read 2 more answers
A wheel is rotating at 30.0 rpm. The wheel then accelerates uniformly to 50.0 rpm in 10.0 seconds. Determine the – a) rate of an
Mademuasel [1]

Answer:

The angular acceleration is 0.209\ rad/s^2

Explanation:

Given that,

Angular velocity, \omega_{i} = 30.0\ rpm

Angular velocity, \omega_{f} = 50.0\ rpm

Time t = 10.0 sec

We need to calculate the angular acceleration

Using formula of angular acceleration

\alpha=\dfrac{\Delta \omega}{\Delta t}

\alpha=\dfrac{\omega_{f}-\omega_{i}}{\Delta t}

\alpha=\dfrac{50.0-30.0}{10.0}

Now, we change the angular velocity in rad/s.

\omega=20\times\dfrac{2\pi}{60}

\omega=2.09\ rad/s

\alpha=\dfrac{2.09}{10.0}

\alpha=0.209\ rad/s^2

Hence, The angular acceleration is 0.209\ rad/s^2

5 0
3 years ago
Read 2 more answers
A spool whose inner core has a radius of 1.00 cm and whose end caps have a radius of 1.50 cm has a string tightly wound around t
White raven [17]

Answer:

v₁ = 37.5 cm / s

Explanation:

For this exercise we can use that angular and linear velocity are related

        v = w r

in the case of the spool the angular velocity for the whole system is constant,

They indicate the linear velocity v₀ = 25.0 cm / s for a radius of r₀ = 1.00 cm,

         w = v₀ /r₀

for the outside of the spool r₁ = 1.5 cm

         w = v₁ / r₁1

since the angular velocity is the same we set the two expressions equal

        \frac{v_o}{r_o} = \frac{v_1}{r_1}

        v1 = \frac{r_1}{r_o} \ \ v_o

let's calculate

       v₁ = \frac{1.50}{1.00} \ \ 25.0

       v₁ = 37.5 cm / s

4 0
3 years ago
according to newton's third law, when a horse pulls on a cart, the cart pulls back on the horse with an equal force on the horse
Debora [2.8K]
Based on Newton's principle, whenever objects A and B interact with each other, they exert forces upon each other.

When a horse pulls on a cart, t<span>he horse exerts a force only to the cart. But that force applies only to the cart, not to the horse.
 
The cart in turn exerts a force on the horse. But that force applies only to the horse, not the cart also.
</span>
There are two forces resulting from this interaction - a force on the horse and a force on the cart. T<span>he net force on the cart remains as it was --- a positive force in the direction of the horse's movement. Therefore, the cart begins to accelerate and move.</span><span>


</span>
8 0
3 years ago
You are trying to measure the mass of several different objects when you realize that there is a large wad of gum stuck to the u
nadya68 [22]

Answer:

accuracy

Explanation:

You are trying to measure the mass of several different objects when you realize that there is a large wad of gum stuck to the underside of the balance pan. Removing the gum will improve the <u>accuracy</u> of your measurements.

6 0
2 years ago
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