Answer:
Explanation:
Use Dalton's law and the vapor pressure of water at 23.0 o C to correct the pressure to units of atmoshperes.
PT = Poxygen +Pwater
At 23.0 o C the vapor pressure of water is 21.1 mmHg. (This can be found on a vapor pressure table.)
762 mmHg = Poxygen + 21.1 mmHg
Poxygen = 762 mmHg - 21.1 mmHg
Poxygen =741 mmHg
Convert the corrected pressure to atmospheres.
(741 mmHg) (1 atm / 760 mmHg) = 0.975 atm
Use the ideal gas law to find out how many moles of gas were produced:
PV = nRT (remember to put volume in liters and temperature in Kelvin)
(0.975 atm) (.193 L) = n (.0821 L atm / mol K) (298 K)
n = (0.975 atm) (.193 L) / (.0821 L atm / mol K) (298 K)
n = 7.69 X 10-4 mol
Use the number of moles and the molecular weight of oxygen to find out how many grams of oxygen were collected.
(7.69 X 10-4 mol) (32.0 g / 1 mol) = 2.46 X 10-2 g
Answer:
defined as a process in which mo heat transfer take place
Explanation:
is a process which occurs without transferring heat /mass between the system and it's surrounding.
Answer:
0.7246 M
Explanation:
Considering:
Or,
Given :
For 
:
Molarity = 2.086 M
Volume = 188.9 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 188.9×10⁻³ L
Thus, moles of :
Moles of = 0.39405 moles
For NaOH :
Molarity = 0.4607 M
Volume = 269.3 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 269.3×10⁻³ L
Thus, moles of NaOH :
Moles of NaOH = 0.1241 moles
According to the given reaction:
1 moles of react with 2 moles of NaOH to form 1 mole of sodium sulfate.
Thus,
2 moles of NaOH react with 1 mole of
1 mole of NaOH react with 1/2 mole of
0.1241 moles of NaOH react with (1/2)×0.1241 mole of
Moles of that got reacted = 0.06205 moles
Unreacted moles = Total moles - Moles that got reacted = 0.39405 - 0.06205 moles = 0.332 moles
Total volume = 188.9×10⁻³ L + 269.3×10⁻³ L = 458.2×10⁻³ L
Concentration of :
<u>Concentration of = 0.7246 M</u>
I know that neutrons start nuclear rxns similar to this like Uranium-238. So I am going to say true.
<span>10 g of hexane has a greater volume than 10 g of toluene.
volume of hexane = 15.27 mL
volume of toluene = 11.53 mL
First, look up the density of hexane and toluene.
hexane = 0.6548 g/mL
toluene = 0.867 g/mL
Since hexane has the lower density, the same mass of hexane will have a higher volume than the same mass of toluene. No need for you to actually calculate the volume for the first part of the question.
However, the 2nd part of the question does require you to calculate the volume. That is a simple matter of division.
volume of hexane = 10 g / 0.6548 g/mL = 15.27 mL
volume of toluene = 10 g / 0.867 g/mL = 11.53 mL</span>
