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madreJ [45]
3 years ago
7

In relation to chemical solutions, which term does not express a degree of saturation?

Chemistry
2 answers:
klio [65]3 years ago
8 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

From the given options:

<u>Option A:</u> Unsaturated solution is defined as the solution in which more solute particles can be dissolved in the solvent.

<u>Option B: </u>Saturated solution is defined as the solution in which no more solute particles can be dissolved in the solvent.

<u>Option C:</u> Supersaturated solution is defined as the solution in which more amount of solute particles is present than the solvent particles.

<u>Option D:</u> Oversaturated is defined as the to saturate the solution excessively or to provide with more amount of substance for saturation.

Hence, the correct answer is Option D.

Marizza181 [45]3 years ago
4 0
The answer is D. oversaturated. The term to represent the solution contains more solid solute than saturated solution is supersaturated, not oversaturated.
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solniwko [45]

Answer:

110

Explanation:

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3 years ago
To name the compound written as CuCl2, you would write:
vovangra [49]

Answer: option C. Copper (II) chloride

Explanation:

To name CuCl2, we need to know the oxidation state of Cu in the compound as chlorine always have oxidation on —1 in all its compound. The oxidation state of Cu can be calculated as follows:

Cu + 2Cl = 0 (since the compound has no charge)

Cl = —1

Cu + 2(—1) = 0

Cu —2 = 0

Collect like terms

Cu = 0 +2

Cu = +2

Therefore, the oxidation state of Cu in CuCl2 is +2.

The name of the compound will be copper(ii) chloride, since cupper has oxidation state +2 in the compound.

4 0
2 years ago
72.0 grams of water how many miles of sodium with react with it?
Flura [38]

Answer:

\large \boxed{\text{8.00 mol}}

Explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

Mᵣ:                  18.02

            2Na + H₂O ⟶ 2NaOH + H₂

m/g:                72.0  

2. Moles of H₂O

\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g  H$_{2}$O}} = \text{3.996 mol H$_{2}$O}

3. Moles of Na

The molar ratio is 2 mol Na/1 mol H₂O.

\text{Moles of Na} =  \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}

7 0
3 years ago
Consider the following reaction between calcium oxide and carbon dioxide: CaO(s)+CO2(g)→CaCO3(s) A chemist allows 14.4 g of CaO
sweet-ann [11.9K]

Answer:

Theoretical yield =26.03 g

Percent yield = 87%

Limiting reactant = CaO

Explanation:

Given data:

Mass of CaO = 14.4 g

Mass of CO₂ = 13.8 g

Actual yield of CaCO₃ = 22.6 g

Theoretical yield = ?

Percent yield = ?

Limiting reactant = ?

Solution:

Chemical equation:

CaO + CO₂   → CaCO₃

Number of moles of CaO:

Number of moles  = Mass /molar mass

Number of moles = 14.4 g / 56.1 g/mol

Number of moles  = 0.26 mol

Number of moles of CO₂:

Number of moles = Mass /molar mass

Number of moles = 13.8 g / 44 g/mol

Number of moles = 0.31 mol

Now we will compare the moles of CO₂ and CaO with CaCO₃ .

                  CO₂         :                CaCO₃  

                  1               :                 1

                 0.31           :              0.31

                CaO           :               CaCO₃  

                 1                :                 1

                 0.26         :              0.26

The number of moles of  CaCO₃ produced by CaO are less it will be limiting reactant.

Mass of CaCO₃: Theoretical yield

Mass of CaCO₃ = moles × molar mass

Mass of CaCO₃ =0.26 mol × 100.1 g/mol

Mass of CaCO₃ =  26.03 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 22.6 g/ 26.03 g × 100

Percent yield = 0.87× 100

Percent yield = 87%

Limiting reactant:

The number of moles of  CaCO₃ produced by CaO are less it will be limiting reactant.

7 0
3 years ago
A group of students is investigating whether aluminum is a better thermal conductor than steel. The students take an aluminum wi
Mademuasel [1]

The students have conducted an experiment to check their hypothesis on the thermal conductivity of two metals; Aluminum and steel. The experimental observations have been noted, and the next step based on the scientific procedure is to analyze the data.

Analysis of data suggests that; since the length of wax after 10 min is lower in Al than steel, aluminum is a better thermal conductor.

Ans B) Analyze the data

7 0
3 years ago
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