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lakkis [162]
3 years ago
10

How many moles of steam are produced when 5.74 moles of octane (C8H18) react?

Chemistry
1 answer:
crimeas [40]3 years ago
3 0
This is a combustion reaction, which always has the hydrocarbon and oxygen as reactants and then carbon dioxide and water (which is steam in this case) as products.

C8H18 + O2 —> CO2 + H2O

Balance your carbons first. You want to get 8 carbons on both sides.

C8H18 + O2 —> 8CO2 + H2O

Now balance your hydrogens. You want 18 hydrogens on both sides.

C8H18 + O2 —> 8CO2 + 9H2O

Now balance your oxygens. You have 2 on the left and 25 on the right. The O2 reactant needs a coefficient of 12.5 to balance this.

C8H18 + 12.5O2 —> 8CO2 + 9H2O

However, you can’t have decimals for coefficients in a reaction. So, multiply everything by 2.

2C8H18 + 25O2 —> 16CO2 + 18H2O

Now, use your mole ratio of 18 mol H2O for every 2 mol C8H18 to solve.

5.74 mol C8H18 • (18 mol H2O / 2 mol C8H18) = 51.7 mol H2O (steam)
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Calculate the percent mass of sugar in mountain dew: The total mass of the mountain dew solution is 300g and there are 231 g of
s2008m [1.1K]

Answer:

c. 77 %

Explanation:

Percent mass (% mass) of solute = mass of solute/mass of solution × 100

According to this question, a mountain dew solution weighing 300grams contains 231 g of sugar. This means that:

% mass of sugar = 231g/300g × 100

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4 0
2 years ago
Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =
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Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )

Wherem  

k_1\ is\ the\ rate\ constant\ at\ T_1

k_2\ is\ the\ rate\ constant\ at\ T_2

E_a is the activation energy

R is Gas constant having value = 8.314 J / K mol  

Thus, given that, E_a = ?

k_2=4.0\times 10^3s^{-1}

k_1=1.5\times 10^3s^{-1}  

T_1=5\ ^0C  

T_2=25\ ^0C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (5 + 273.15) K = 278.15 K  

T = (25 + 273.15) K = 298.15 K  

T_1=278.15\ K

T_2=298.15\ K

So,

\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)

E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}

E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}

E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}

E_a=33813.28\ J/mol

<u>The activation energy for the decomposition = 33813.28 J/mol</u>

8 0
3 years ago
Which compound would you expect to be soluble in the nonpolar solvent carbon disulfide?
ch4aika [34]

Answer:

hexane C6H14

IS YOUR ANSWER

Explanation:

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8 0
2 years ago
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