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3 years ago

How many moles of steam are produced when 5.74 moles of octane (C8H18) react?

1 answer:

3 0

This is a combustion reaction, which always has the hydrocarbon and oxygen as reactants and then carbon dioxide and water (which is steam in this case) as products.

C8H18 + O2 —> CO2 + H2O

Balance your carbons first. You want to get 8 carbons on both sides.

C8H18 + O2 —> 8CO2 + H2O

Now balance your hydrogens. You want 18 hydrogens on both sides.

C8H18 + O2 —> 8CO2 + 9H2O

Now balance your oxygens. You have 2 on the left and 25 on the right. The O2 reactant needs a coefficient of 12.5 to balance this.

C8H18 + 12.5O2 —> 8CO2 + 9H2O

However, you can’t have decimals for coefficients in a reaction. So, multiply everything by 2.

2C8H18 + 25O2 —> 16CO2 + 18H2O

Now, use your mole ratio of 18 mol H2O for every 2 mol C8H18 to solve.

5.74 mol C8H18 • (18 mol H2O / 2 mol C8H18) = 51.7 mol H2O (steam)

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Two solutions are combined in a beaker. One solution contains 500.0 g of potassium phosphate and the other contains 500.0 g of c

Anna [14]

The question is incomplete. The complete question is

Two solutions are combined in a beaker. One solution contains 500.0 g of potassium phosphate and the other contains 500.0 g of calcium nitrate. A double displacement reaction occurs. What mass of each of the following substances is present when the reaction stops. A) potassium phosphate remaining B) calcium nitrate g remaining C) calcium phosphate formed D) potassium nitrate g formed

Answer:

a)84.91g

b)8.20g

c)316.4g

d)616.73g

Explanation:

The equation of the reaction:

2K3PO4(aq) + 3Ca(NO3)2 (aq)-------> 6KNO3(aq) + Ca3(PO4)2(s)

Molar mass of potassium phosphate= 212.27 g/mol

Amount of potassium phosphate= 500/212.27= 2.4 moles

Molar mass of calcium nitrate= 164.088 g/mol

Amount of calcium nitrate= 500/164.088=3.05moles

a) amount of potassium phosphate reacted according to reaction equation= 2 moles

Amount of potassium phosphate remaining= 2.4-2=0.4 moles

Mass of potassium phosphate remaining= 0.4×212.27=84.91g

b) Amount of calcium nitrate reacted according to reaction equation=3

Amount of calcium nitrate remaining=3.05-3= 0.05

Mass of calcium nitrate remaining= 0.05×164.088= 8.20g

c) since calcium nitrate is the limiting reactant, we use to estimate the mass of products formed.

From the reaction equation,

3 moles of calcium nitrate yields 1 mole of calcium phosphate

3.05 moles of calcium nitrate yields 3.05/3 = 1.02 moles of calcium phosphate

Molar Mass of calcium phosphate= 310.18 g/mol

Mass of calcium phosphate produced= 1.02×310.18= 316.4g

3 moles of calcium nitrate yields 6 moles of potassium nitrate

3.05 moles of calcium nitrate yields 3.05×6/3= 6.1 moles of potassium nitrate

Molar mass of potassium nitrate = 101.1032 g/mol

Mass of potassium nitrate formed= 6.1× 101.1032= 616.73g

6 0

3 years ago

what is the best course of action if solid material remains in the flask after the heating step of recrystallization

lys-0071 [83]

Answer:

filter the hot mixture.

Explanation:

Solid is stayed undissolved since the arrangement is gotten super saturated. On the off chance that solid molecule is available recrysallization won't happen in this way we need expel the solid molecule by filtarion in hot condition itself . Subsequently, arrangement become totally homogenous and recrysallization item will shaped by moderate cooling

7 0

3 years ago

Calcule la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) que se preparó al mezclar, en un recipiente aforado, 4 mo

oee [108]

Considerando la definición de molaridad, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 $\frac{moles}{litro}$ .

La molaridad es una medida de la concentración de un soluto en una disolución que se define como el número de moles de soluto que están disueltos en un determinado volumen.

La molaridad de una solución se calcula dividiendo los moles del soluto por el volumen de la solución:

$Molaridad=\frac{numero de moles de soluto}{volumen}$

La Molaridad se expresa en las unidades $\frac{moles}{litro}$ .

En este caso, sabes que una solución acuosa se preparó al mezclar 4 moles del ácido con suficiente agua hasta completar 8 litros de solución. Entonces, sabes que:

número de moles de soluto= 4 moles
volumen= 8 litros

Reemplazando en la definición de molaridad:

$Molaridad=\frac{4 moles}{8 litros}$

Resolviendo:

Molaridad= 0.5 $\frac{moles}{litro}$

Finalmente, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 $\frac{moles}{litro}$ .

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2 years ago

Which organic compound is correctly matched with the subunit that composes it?

Alex787 [66]

It is the Starch-glucose. Glucose is a solitary sugar particle that your body can retain specifically in the digestive system. Sucrose and starches are starches shaped by at least two sugars reinforced together. The sugars in sucrose and starch must be separated into glucose particles in the gastrointestinal tract before your digestive organs can assimilate them.

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3 years ago

Name a common greenhouse gas with only hydrogen and oxygen

AVprozaik [17]

I'm guessing water vapour. i can't think of any other gas limited to only hydrogen and oxygen

hope it helps :)

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3 years ago