When you assume that the gas is behaving ideally, the gas molecules are very far from each other that they do not have any intermolecular forces. If it behaves this way, you can assume the ideal gas equation:
PV = nRT, where
P is the pressure
V is the volume
n is the number of moles
R is a gas constant
T is the absolute temperature
When the process goes under constant pressure (and assuming same number of moles),
P/nR = T/V = constant, therefore,
T₁/V₁=T₂/V₂
If V₂ = V₁(1+0.8) = 1.8V₁, then,
T₂/T₁ = 1.8V₁/V₁
Cancelling V₁,
T₂/300=1.8
T₂ =540 K
If you do not assume ideal gas, you use the compressibility factor, z. The gas equation would now become
PV =znRT
However, we cannot solve this because we don't know the value of z₁ and z₂. There will be more unknowns than given so we won't be able to solve the problem. But definitely, the compressibility factor method is more accurate because it does not assume ideality.
The molality of a solution is expressed as the amount of the solute in moles per mass of the solvent in kilograms. In this case, the molality is equal to 400 g/62.07 g/mol/ 4 kg water. The molality is equal to 1.61 molal. The freezing point depression is determined through Tf- Kb*molality. Substituting, 0 deg - 1.86 * 1.61 m is equal to -2.99 degrees celsius.
Hey there: !
density = 19.32 g/cm³
mass = 54.82 g
Volume = ?
therefore:
D = m / V
19.32 = 54.82 / V
V = 54.82 / 19.32
V = 2.837 cm³
The charge of an aluminum ion is typically 3+. This is because the element's atomic number is 13, reflecting the fact that it has 13 electrons and 13 protons. The valence shell of aluminum has three electrons, and per the octet rule, these three electrons are lost resulting in just 10 electrons and 13 protons.
Answer:
Mass = 0.008 g
Explanation:
Given data:
Volume of H₂ = 107 mL
Pressure = 104.8 KPa
Temperature = 30°C
Mass of H₂ present = ?
Solution:
Formula:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the units of temperature, pressure and volume.
Temperature = 30+273 = 303 K
Volume of H₂ = 107 mL (107/1000= 0.107 L)
Pressure = 104.8 KPa (104.8/101 = 1.04 atm)
by putting values,
1.04 atm ×0.107 L = n× 0.0821 atm.L/ mol.K × 303 K
0.11 atm.L = n×24.87 atm.L/ mol
n = 0.11 atm.L / 24.87 atm.L/ mol
n = 0.004
Mass of H₂:
Mass = number of moles × molar mass
Mass = 0.004 mol × 2 g/mol
Mass = 0.008 g