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3 years ago

Convert 0.0078 gallons to centiliters (1 gallons =3.785L)

Chemistry

1 answer:

Leokris [45]3 years ago

5 0

Answer:

2.95 centiliters

Explanation:

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You are given 3.0 grams of solid sodium to react to pure water which has a molarity of 55.6 M. How many milligrams of H2 can be

serious [3.7K]

Answer:

= 15.51 mL

Explanation:

Here's is the reaction:

2HgO(s) ⇒ 2 Hg(s)+O₂(g)

In this reaction 2mol HgO = 1mol O₂

The molecular weight of HgO = 216.59g

so, 3.0g HgO = 3.0g x 1.00molHgO/216.59gHgO

= 0.0138511 molHgO

The amount of Oxygen follows:

0.0138511 molHgOx1/2= 0.00692555 mol O₂

Now, volume of 1 any gas = 22400mL

so, 0.00692555 mol O₂ x22400mLO₂/1mol O₂

= 15.513232mL O₂

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3 years ago

How high did Joseph Kittinger get up into the atmosphere before he jumped?

Trava [24]

I know the answers I do

8 0

2 years ago

Read 2 more answers

Match each transition metal ion with its condensed ground-state electron configuration. A [Ar]3d2 B [Ar]4s23d3 C [Kr]4d10 D [Xe]

madreJ [45]

Answer:

$Mn^{2+}$ : - F . $[Ar]3d^{5}$

$Hg^{2+}$ : - G. $[Xe]4f^{14}5d^{10}$

$La^{3+}$ : - D. $[Xe]$

$Fe^{3+}$ : - F. $[Ar]3d^{5}$

$Ag^{+}$ : - C. $[Kr]4d^{10}$

$Co^{3+}$ : - E. $[Ar]3d^{6}$

Explanation:

The electronic configuration of the element Mn is:-

$[Ar]3d^{5}4s^2$

For, $Mn^{2+}$ , 2 electrons are lost, thus the configuration is:-

$[Ar]3d^{5}$

The electronic configuration of the element Hg is:-

$[Xe]4f^{14}5d^{10}6s^2$

For, $Hg^{2+}$ , 2 electrons are lost, thus the configuration is:-

$[Xe]4f^{14}5d^{10}$

The electronic configuration of the element La is:-

$[Xe]5d^{1}6s^2$

For, $La^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Xe]$

The electronic configuration of the element Fe is:-

$[Ar]3d^{6}4s^2$

For, $Fe^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Ar]3d^{5}$

The electronic configuration of the element Ag is:-

$[Kr]4d^{10}5s^1$

For, $Ag^{+}$ , 1 electron is lost, thus the configuration is:-

$[Kr]4d^{10}$

The electronic configuration of the element Co is:-

$[Ar]3d^{7}4s^2$

For, $Co^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Ar]3d^{6}$

7 0

3 years ago

What quantity in moles of HCl are there in 35.0 mL of 0.350 M HCl?

marta [7]

Answer:

0.0123 moles

Explanation:

Concentration = Moles / Volume of solution

or you can rearrange the formula to get

Moles = concentration (moles/liter) x volume of solution (liter)

First convert your volume to L instead of mL. 35mL = 0.035L

moles = 0.350 moles/liter x 0.035 liter (liters cancel out)

moles = 0.0123

5 0

2 years ago

How many is 1 min = ? km

Ivan

1 minute equals 60 kph.........Thanks Tionne17 for asking!!!

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3 years ago