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worty [1.4K]
1 year ago
15

the grade of coal increases with (remember a higher grade of coal means it produces more energy when burned) quizlet

Chemistry
1 answer:
Aleks04 [339]1 year ago
5 0

The grade of coal increases with compaction.

<h3>What is Compaction?</h3>

When something is crushed or compressed, it becomes compacted. After being collected, trash is often compressed to make it smaller and take up less room. Compaction is the process of making anything more compact, dense, or firmly packed.

grade of coal - The highest grade of coal is anthracite. It is a black, glossy, hard, brittle coal that is frequently referred to as hard coal. It has a high proportion of fixed carbon and a low proportion of volatile matter. Between subbituminous and anthracite, bituminous coal is the intermediate rank of coal.

to learn more about  compaction go to -

brainly.com/question/2837181

#SPJ4

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Identify what type of reaction is below. Also determine what coefficients that would balance the chemical equation.
pantera1 [17]

Answer:

4HCl + 2Zn = 2H2 + 2ZnCl2

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Is cutting your hair a physical or chemical change
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Acetylene gas (ethyne; HC = CH) burns in an oxyacetylene torch to produce carbon dioxide and water vapor. The heat of reaction f
Yanka [14]

The mass of CO2 produced by 26g of acetylene is 88g.

Given ,

In an oxyacetylene torch, acetylene gas (ethyne; HCCH) burns to produce carbon dioxide and water vapour.

The acetylene combustion reaction is given by,

H2O + HCCH + 5/2 O=O 2CO2

Heat of reaction for acetylene combustion = 1259kj/mol

CO2 has a molecular mass of 44g/mol.

2 moles of CO2 have a molecular mass of 88g.

On combustion, 1 mole of acetylene yields 2 moles of CO2.

Thus, 26g of acetylene produces 88g of CO2 when burned.

As a result, the mass of carbon dioxide produced by 26g of acetylene is 88g.

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6 0
1 year ago
PLEASE HELP ME
vichka [17]
Light moves in a straight line except at surfaces between different transparent materials, where its path bends.
4 0
3 years ago
How many moles of propane gas would be present in 11 grams<br> of the gas at standard conditions?
Akimi4 [234]
The molar mass is usually referred to with
M
, while the mass is referred to as
m
. The amount of substance is
n
. This gives you the following relationship:
=
M
=
m
n

Since you have given (C3H8)=11 g
m
(
C
3
H
8
)
=
11

g
and you already looked up (C3H8)=44.1 gmol−1
M
(
C
3
H
8
)
=
44.1

g
m
o
l
−
1
, you can use this formula to determine (C3H8)
n
(
C
3
H
8
)
.

In this question it is quite hard to explain the use of significant figures. Those are used to imply a certain inaccuracy. Not enough information is given by the question, as of how accurate the measurement is. It is a mere exercise of converting one property into another. Here you should not worry about it.
5 0
2 years ago
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