3 A rocket of mass 1200 kg is travelling at 2000 m/s. It fires its engine for 1 minute. The forward thrust provided by the rocke
1 answer:
The impulse shared by the object equals the difference in momentum of the object. In equation form,
F • t = m • Δ v. In a collision, objects experience an impulse; the impulse causes and is equal to the difference in momentum.
<h3>How to calculate thrust provided by the rocket engines is 10 kN (10 000 N).?</h3>
a)There is this impulse-momentum change equation.
We consider everything exits happen along a straight line, and gravitation does not participate.
So, the increase of momentum is F×t = 10000 N × 60 seconds = 600000 N*s = 600000 (kg*m)*s/s^2 = 600000 kg*m/s.
New velocity after engine was firing during 60 seconds is 2000 + 500 = 2500 m/s.
To learn more about Impulse-momentum, refer
#SPJ9
You might be interested in
<h2>Answer:</h2>
<em>1.33 x 10⁻ ⁴ T outwards.</em>
<em></em>
<h2>Explanation:</h2>The equation for the magnetic force (F) on a wire whose length is L and carrying a current I in a magnetic field (B) that is uniform is given by;
F = ILB sin θ ---------------------(i)
Where;
θ = angle between the direction of the current and that of the magnetic field.
From the question,
F = 4.0 × 10⁻² N
I = 12A
L = 25m
θ = 90°
<em>Substitute these values into equation(i) and solve as follows;</em>
4.0 × 10⁻² = 12 x 25 x B x sin 90°
4.0 × 10⁻² = 300 x B x 1
4.0 × 10⁻² = 300B
0.04 = 300B
B =
B = 0.000133
B = 1.33 x 10⁻ ⁴ T
To get the direction of the magnetic field, the right-hand rule is used.
If the right hand fingers are positioned in the correct order specified by the right hand rule, then it would be seen that the magnetic field is directed outwards.
Therefore, the magnitude and direction of the magnetic field at this location is <em>1.33 x 10⁻ ⁴ T outwards.</em>