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BlackZzzverrR [31]
2 years ago
9

You are standing in front of a pool of water and see your face in the water but when a stone is dropped into the pool you no mor

e see your face
Explain why please ​
Physics
1 answer:
Wewaii [24]2 years ago
4 0

Answer:

• Before, the water is calm with a regular reflection surface. So, all the light rays from your face will be reflected directly to your eyes hence viewing your face clearly.

• After throwing a stone in the pool, the water distorts or disorganises due to change in volume and molecular dislocation. So, it forms an irregular reflecting surface. Hence, all light rays from the face are reflected in different directions hence you can't see your face clearly.

Explanation:

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vampirchik [111]

Question: A loader sack of total mass

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gravity of the load.​

Answer:

19.6 Joules

Explanation:

Applying

W = mgh........................ Equation 1

Where W = Workdone by gravity on the load, m = mass of the loader sack, h = height, g = acceleration due to gravity

From the question,

Given: m = 1000 grams = (1000/1000) kilogram = 1 kg, h = 200 cm = 2 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

W = (1×2×9.8)

W = 19.6 Joules

Hence the work done by gravity on the load is 19.6 Joules

8 0
3 years ago
What is one way that early scientific practice differed from modern scientific practice?
mote1985 [20]
Early hypotheses were not based on observations.
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6 0
3 years ago
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A student calculates the density of a copper cube to be 4.15 g/cm . If the accepted value is 8.64 g/cm the percentage error in h
Helen [10]

 The percentage error in his experimental value is -51.97%.

<h3>What is percentage error?</h3>

This is the ratio of the error to the actual measurement, expressed in percentage.

To calculate the percentage error of the student, we use the formula below.

Formula:

  • Error(%) = (calculated value-accepted value)100/(accepted............. Equation 1

From the question,

Given:

  • Calculated value = 4.15 g/cm
  • accepted value = 8.64 g/cm

Substitute these values into equation 1

  • Error(%) = (4.15-8.64)100/8.64
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Hence, The percentage error in his experimental value is -51.97%.

Learn more percentage error here: brainly.com/question/5493941

8 0
2 years ago
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Answer:

The output out be 200

Explanation:

Hope this helps :))

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OlgaM077 [116]

Answer:this is confusing and what subject is this

Explanation:

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