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3 years ago

9

If the mass of a material is 45 grams and the volume of the material is 10 cm^3, what would the density of the material be

1 answer:

umka2103 [35]3 years ago

4 0

81.4/m3 is my answer

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A firecracker in a coconut blows the coconut into three pieces. Two pieces of equal mass fly off south and west, perpendicular t

Lisa [10]

Explanation:

Let us assume that piece 1 is $m_{1}$ is facing west side. And, piece 2 is $m_{2}$ facing south side.

Let $m_{1} \text{and} m_{2}$ = m and $m_{3}$ = 2m. Hence,

$2mv_{3y} = m(21)$

$v_{3y} = \frac{21}{2}$

= 10.5 m/s

$2mv_{3x} = m(21)$

$v_{3x} = \frac{21}{2}$

= 10.5 m/s

$v_{3} = \sqrt{v^{2}_{3x} + v^{2}_{3y}}$

= $\sqrt{(10.5)^{2} + (10.5)^{2}}$

= 14.84 m/s

or, = 15 m/s

Hence, the speed of the third piece is 15 m/s.

Now, we will find the angle as follows.

$\theta = tan^{-1} (\frac{v_{3y}}{v_{3x}})$

= $tan^{-1}(\frac{10.5}{10.5})$

= $tan^{-1} (45^{o})$

= $45^{o}$

Therefore, the direction of the third piece (degrees north of east) is north of east.

5 0

3 years ago

Find the kenetic energy of a car of mass 700kg racing with a velocity of 10m/s

fiasKO [112]

Answer:

35000 KJ

Explanation:

The equation for the kinetic energy is given by the formula :

$E_{k} = \frac{1}{2} mv^{2}$

$E_{k} = \frac{1}{2} (700)(10)^{2}$

$E_{k} = \frac{1}{2} (700)(100)$

$E_{k} = (350)(100)$ OR $E_{k} = \frac{1}{2} (70000)$

$E_{k} = 35000$

Units will be kilojoules since the units of mass was kilograms .

Our final answer is 35000 KJ

Hope this helped and have a good day

5 0

2 years ago

What happens to the frequency and pitch of sound if the object making the sound moves away from you ?

Olin [163]

If you and the source of sound are moving apart, then the pitch (frequency) <em>you hear</em> is <em>lower</em> than the pitch (frequency) that's actually leaving the source.

It doesn't matter whether you or the source is the one moving, only that the distance between you is increasing.

8 0

3 years ago

A published hypothesis:

kow [346]

Answer:

should be tested by the scientific community

4 0

3 years ago

Calculate the molecular weight of Aluminium hydroxide

Vedmedyk [2.9K]

Al(OH)3 = 26.98 + [(16×3) + (1.01×3)] = 26.98 + 51.03 = 78.01 and the unit will be g/mol

<h3><em>Al(OH)3 = 78.01 g/mol</em></h3>

5 0

3 years ago