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Savatey [412]
3 years ago
9

If the mass of a material is 45 grams and the volume of the material is 10 cm^3, what would the density of the material be

Physics
1 answer:
umka2103 [35]3 years ago
4 0
81.4/m3 is my answer

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You can make a solute dissolve more quickly in a solvent by
Gekata [30.6K]

Answer:Stirring.

Explanation:Stirring a solute into a solvent speeds up the rate of dissolving because it helps distribute the solute particles throughout the solvent. For example, when you add sugar to iced tea and then stir the tea, the sugar will dissolve faster.

3 0
2 years ago
The distance between two successive maximaof
denpristay [2]

Answer:

v = 1.224 m/s

Explanation:

given,                          

distance between the two successive maxima = 1.70 m

number of crest = 8          

time = 11 s                            

frequency is equal to number of cycle per secod

f = \dfrac{8}{11}          

f = 0.72\ Hz                

velocity of wave

v = f x λ                

v = 0.72 x 1.70        

v = 1.224 m/s          

Hence, the wave speed is equal to v = 1.224 m/s

4 0
3 years ago
Which of the following accurately describes the way in which a muscle moves?
Vaselesa [24]
<h3><u>Answer</u>;</h3>

B. When actin filaments are pulled toward the center of the sarcomere, the fiber shortens.

<h3><u>Explanation;</u></h3>
  • <em><u>The events of muscle fiber shortening occurs with in the sacromeres in the fibers. </u></em>
  • <em><u>Contraction of striated muscle fibers takes place as the sacromeres shorten as myosin heads pull on the actin filaments.</u></em>
  • <em><u>Filament movement starts at the region or zone where thin and thick filaments overlap. </u></em>
  • <em><u>Myofibril contains many sacromeres along its length and thuse myofibrils and muscle cells contract as the sacromeres contract.</u></em>
7 0
2 years ago
A load of 54 N attached to a spring that ishanging vertically stretches the spring 0.15 m.What is the spring constant?Answer in
beks73 [17]

Answer:

300 N/m

Explanation:

given,

Load attached to the spring, W = 54 N

length of stretch of the spring, x = 0.15 m

spring constant= ?

Force applied on the spring is calculated by the equation

F = k x

where k is the spring constant

x is the displacement of the spring due to applied load

now,

54 = k × 0.15

k = \dfrac{54}{0.15}

k =300\ N/m

hence, the spring constant is equal to 300 N/m

8 0
3 years ago
Read 2 more answers
The distance traveled by an object can be modeled by the equation d = ut + 0.5at2 where d = distance, u = initial velocity, t =
Taya2010 [7]
We are given with the expression d = ut + 0.5 at^2 and is asked to express the equation in terms of a. First, we transpose ut to the left side, then we multiply to the equation and divide lastly the resulting equation by t^2. The final expression becomes a = 2(d-ut)/t^2.
8 0
3 years ago
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