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eduard
2 years ago
11

Una clase de geometría tiene un total de 46 estudiantes. El número de mujeres es 12 menos que el número de hombres. ¿Cuántos hom

bres y cuántas mujeres están en la clase?
Mathematics
1 answer:
Lunna [17]2 years ago
4 0

En la clase de geometría hay 29 hombres y 17 mujeres.

<h3>System of Linear Equations</h3>

A system of linear equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point at which the lines intersect.

You can solve a linear system by the adding or substitution methods. In the addition method, you eliminate a variable, on the other hand, in the substitution method you replace a variable for the other. For solving this question, you will apply the  substitution method.

The question gives:

  • número de mujeres es 12 menos que el número de hombres - m=h-12
  • clase de geometría tiene un total de 46 estudiantes = m+h=46

Then,

m+h=46 (1)

m=h-12  (2)

You should replace equation 2 in the variable m for equation 1. See below

h-12+h=46

2h=46+12

2h=58

h=29

If h=29, from equation 2 you will find m=29-12=17

Read more about solving systems equations here:

brainly.com/question/12691830

#SPJ1

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17. Which of the following equations would graph a line parallel to 3y = x + 5? (
Naddik [55]

The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st

Step-by-step explanation:

Parallel lines have same slopes and different y-intercepts

To find which equation would graph a line parallel to 3y = x + 5

1. Put the equation in the form of y = mx + c

2. m is the slope of the line and c is the y-intercept

3. Look for the equation which has the same values of m and different

   values of c

∵ 3y = x + 5

- Divide each term of the equation by 3 to put the equation in the

 form of y = mx + c

∴ y = \frac{1}{3} x + \frac{5}{3}

∴ m = \frac{1}{3}

∴ c = \frac{5}{3}

The first answer:

∵ 3y = x + 1

- Divide each term of the equation by 3

∴ y = \frac{1}{3} x + \frac{1}{3}

∴ m = \frac{1}{3}

∴ c = \frac{1}{3}

∵ The two equations have same slope m = \frac{1}{3}

∵ The two equations have different y-intercepts c = \frac{5}{3}

   and c = \frac{1}{3}

∴ 3y = x + 5 and 3y = x + 1 represent two parallel lines

The equation 3y = x + 1 would graph a line parallel to 3y = x + 5

Learn more:

You can learn more about slope of a line in brainly.com/question/12954015

#LearnwithBrainly

8 0
3 years ago
Find the zeros of y = x + 6x- 4 by completing the square.
dsp73

Answer:

\large\boxed{x=-3\pm\sqrt{13}}

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\\\x^2+6x-4=0\qquad\text{add 4 to both sides}\\\\x^2+2(x)(3)=4\qquad\text{add}\ 3^2=9\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=4+9\\\\(x+3)^2=13\Rightarrow x+3=\pm\sqrt{13}\qquad\text{subtract 3 from both sides}\\\\x=-3\pm\sqrt{13}

8 0
3 years ago
93, 94, 95, 89, 85, 82, 87, 85, 84, 80, 78, 78, 84, 87, 90.
artcher [175]

Answer:

86 is the mean and the median is 85

Step-by-step explanation:

To calculate the mean all u gotta do is add all the numbers then divide by how many numbers there is and to calculate the median all u gotta do is put them in order 78-95 then mark 1 on each side til you reach the middle and the number in the middle is the answer.

6 0
3 years ago
Read 2 more answers
99 POINT QUESTION, PLUS BRAINLIEST!!!
Elden [556K]
We draw region ABC. Lines that connect y = 0 and y = x³ are vertical so:
(i) prependicular to the axis x - disc method;
(ii) parallel to the axis y - shell method;
(iii) parallel to the line x = 18 - shell method.

Limits of integration for x are easy x₁ = 0 and x₂ = 9.
Now, we have all information, so we could calculate volume.

(i)

V=\pi\cdot\int\limits_a^bf^2(x)\, dx\qquad\implies \qquad a=0\qquad b=9\qquad f(x)=x^3


V=\pi\cdot\int\limits_0^9(x^3)^2\, dx=\pi\cdot\int\limits_0^9x^6\, dx=\pi\cdot\left[\dfrac{x^7}{7}\right]_0^9=\pi\cdot\left(\dfrac{9^7}{7}-\dfrac{0^7}{7}\right)=\dfrac{9^7}{7}\pi=\\\\\\=\boxed{\dfrac{4782969}{7}\pi}

Answer B. or D.

(ii)

V=2\pi\cdot\int\limits_a^bx\cdot f(x)\, dx


V=2\pi\cdot\int\limits_0^{9}(x\cdot x^3)\, dx=2\pi\cdot\int\limits_0^{9}x^4\, dx=&#10;2\pi\cdot\left[\dfrac{x^5}{5}\right]_0^9=2\pi\cdot\left(\dfrac{9^5}{5}-\dfrac{0^5}{5}\right)=\\\\\\=2\pi\cdot\dfrac{9^5}{5}=\boxed{\dfrac{118098}{5}\pi}

So we know that the correct answer is D.

(iii)
Line x = h

V=2\pi\cdot\int\limits_a^b(h-x)\cdot f(x)\, dx\qquad\implies\qquad h=18


V=2\pi\cdot\int\limits_0^9\big((18-x)\cdot x^3\big)\, dx=2\pi\cdot\int\limits_0^9(18x^3-x^4)\, dx=\\\\\\=2\pi\cdot\left(\int\limits_0^918x^3\, dx-\int\limits_0^9x^4\, dx\right)=2\pi\cdot\left(18\int\limits_0^9x^3\, dx-\int\limits_0^9x^4\, dx\right)=\\\\\\=2\pi\cdot\left(18\left[\dfrac{x^4}{4}\right]_0^9-\left[\dfrac{x^5}{5}\right]_0^9\right)=2\pi\cdot\Biggl(18\biggl(\dfrac{9^4}{4}-\dfrac{0^4}{4}\biggr)-\biggl(\dfrac{9^5}{5}-\dfrac{0^5}{5}\biggr)\Biggr)=\\\\\\

=2\pi\cdot\left(18\cdot\dfrac{9^4}{4}-\dfrac{9^5}{5}\right)=2\pi\cdot\dfrac{177147}{10}=\boxed{\dfrac{177147\pi}{5}}

Answer D. just as before.

6 0
3 years ago
find the zeros of quadratic polynomial 3x^-2 and verify the relationship between the zeros and the coefficients
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