7.20594 x 10^20
First you must determine how many moles of P3O5 you have. This is done by using the formula
Number of moles (n) = mass in grams of substance (m) /divided by/ Molar mass (M) [this is the sum of the atomic mass of all atoms in the compound]
n = 0.170 / P (31 x 2) + O (16 x 5)
n = 0.170 / 142
n = 0.001197 moles
Then you use avagadros number 6.02 x10^23 this is the number of atoms in one mole of any substance. Since you have 0.001197 moles you multiply the number of moles by avagadros number
0.001197 x (6.02 x 10^23)
= 7.20594 x 10^20 atoms
Answer:
To communicate with each other
Explanation:
Cows use sound (mooing) to communicate with each other and their environment. Cows are herd animals and have complex social structures. Mooing is one way that they interact and how they express their emotions
Answer:
C 108
Explanation:
1 It was found that 4n atoms of metal x
weigh 501.6 g. The relative atomic mass
of X is 209. If n atoms of another metal,
Y, weigh 65.00 g, what is the relative
atomic mass of metal Y?
A 27 B 52 C 108 D 137
if 4n atoms of x weigh 501.6 gm, the n atoms weigh 501.6/4 = 125.4 gms
since the atomic mass is 209, then 6.022 X10^23 atom weigh 209
the ratio of 125.4 to 209 is
125.4/Y =0.6
therefor n is the number of atom in 0.6 moles
if metal Y has the same, number of atoms "n" and weighs 65 gm
then then the relative atomic mass is
65/0.6 =108
so the answer is
C 108
People can feel it because of the Thermal energy.
Explanation:
(a) It is known that relation between energy and mass is as follows.
where, E = energy
m = mass
c = speed of light = 
m/s
As it is given that mass is 
kg. So, putting the given values into the above formula as follows.
= 
= 
Therefore, we can conclude that the energy produced by the reaction between one electron and one positron is .
(b) When gamma ray photons are produced then they will have the same frequency. Relation between energy and frequency is as follows.
E = 
..... (1)
where, h = plank's constant = 
= frequency
Also, ........ (2)
Hence, equating equations (1) and (2) as follows.
= 
So,
=
= 
Thus, we can conclude that the frequency is .
