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enyata [817]
1 year ago
9

Write the following numbers in scientific notation.

Chemistry
1 answer:
IRISSAK [1]1 year ago
7 0

Answer:

a. 5.6x 10^5

b. 3.34 x 10^4

c. 4.120 x 10^-4

d. 1.2 x 10^-4

Explanation:

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The correct answer is C. Executive branch agencies plan their fiscal budgets for the year. (Apex)
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Which of the following is NOT a way that biodiversity is important to an ecosystem?
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A. Biodiversity can increase the rate of extinction

Explanation:

That statement is false because variety is better for a better ecosystem. With variety more can survive in certain situations that others cant.

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A 2.06g sample of agno3•xh2o is dissolved in an aqueous solution of excess nacl. The resulting agcl precipitate is filtered off
irakobra [83]

Answer:

3

Explanation:

NaCl + AgNO₃ ———> NaNO₃ + AgCl.

Firstly, we will need to calculate the number of moles of AgCl produced. That is equal to the mass produced divided by the molar mass of AgCl.

The molar mass of AgCl = 108 + 35.5 = 143.5g/mol

The number of moles is thus 1.32/143.5 = 0.0092 moles

Since silver nitrate and silver chloride contains one atom of silver, it is only possible that their mole ratios are equal. Hence we say that 0.0092 moles of silver nitrate hydrate was dissolved.

Now we go on to calculate the molar mass of the silver nitrate hydrate.

The molar mass is simply the mass divided by the number of moles.

That is 2.06/0.0092 = 223.9 = 224g/mol

We can now calculate the value of x from here.

AgNO3.xH2O

(108 + 14 + 48) + x(2+ 16) = 224

170 + 18x = 224

18x = 224 - 170 = 54

18x = 54

x = 54/18 = 3

8 0
3 years ago
Plz Help me with this ?
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Hey there!

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Hope this helps :)

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A sample of water has a mass of 100.0 g. Calculate the amount of heat required to change the sample from ice at -45.0°C to liqui
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The amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.

<h3>Quantity heat required to convert the ice to liquid</h3>

The total quantity of heat required is calculated as follows;

q(tot) = q1(to ice) + q2(fusion of ice) + q3(liquid)

q(tot) = mcΔθ₁  + mΔHf    +   mcΔθ₂

q(tot) = (100)(4.2)(0 - -45) + (334)(100)  + (100)(4.2)(75 - 0)

q(tot) = 18,900 J  +  33,400 J   +  31,500 J

q(tot) = 18.900 kJ  +  33.400 kJ   +  31.500 kJ

q(tot) = 83,800 J = 83.8 kJ

Thus, the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.

Learn more about quantity of heat here: brainly.com/question/13439286

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8 0
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