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soldier1979 [14.2K]
2 years ago
15

The rate law for the reaction 3A --> 2B is rate = k[A] with a rate constant of 0.0447 hr-1.

Chemistry
1 answer:
Lynna [10]2 years ago
6 0

The half-life of the reaction is determined as 22.4 hr.

<h3>Half life of the reaction</h3>

The half life of the reaction is calculated as follows

rate of reaction, k = Δ[A]/3t = Δ[B]/2t

t = Δ[A]/3k = Δ[B]/2k

where;

  • k is rate constant = 0.0447/hr

t = (3)/(3 x 0.0447) = (2)/(2 x 0.0447) = 22.4 hr

Thus, the half-life of the reaction is determined as 22.4 hr.

Learn more about half life here: brainly.com/question/2320811

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