Question

The rate law for the reaction 3A --> 2B is rate = k[A] with a rate constant of 0.0447 hr-1.

Answer 1

The half-life of the reaction is determined as 22.4 hr.

Half life of the reaction

The half life of the reaction is calculated as follows

rate of reaction, k = Δ[A]/3t = Δ[B]/2t

t = Δ[A]/3k = Δ[B]/2k

where;

• k is rate constant = 0.0447/hr

t = (3)/(3 x 0.0447) = (2)/(2 x 0.0447) = 22.4 hr

Thus, the half-life of the reaction is determined as 22.4 hr.

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