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lukranit [14]
3 years ago
8

If 79.5 mol of an ideal gas is at 8.91 atm at 47.20 °C, what is the volume of the gas?

Chemistry
1 answer:
Eddi Din [679]3 years ago
8 0

Answer:

235L

Explanation:

PV =nRT

V = nRT/P

47.20 °C is 320.35K

V = (79.5 mol)(0.0821 atm•L/mol•K)(320.35K)/8.91atm

V = 234.6698577L

Round to 3 sig figs: 235L

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Answer:

Most substances on earth are compounds and most interesting chemistry is done with compounds. Most interesting chemistry is done with mixtures of compounds although they often start with pure compounds and then do reactions as mixtures. Most chemistry is carried out in liquid solutions made up of compounds that are solids, liquids, or gases in their pure form.

Explanation:

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3 years ago
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What is the balanced equation for solid ammonium nitrate (NH4NO3) decomposes explosively to form nitrogen gas, oxygen gas, and w
Karolina [17]

Answer:

2NH4NO3 —> 2N2 + O2 + 4H2O

Explanation:

We begin by writing the skeletal equation as shown below:

NH4NO3 —> N2 + O2 + H2O

The equation can be balance as follow:

There are 4 atoms of H on the left side of the equation and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:

NH4NO3 —> N2 + O2 + 2H2O

Now we have a total of 4 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 1/2 in front of O2 as shown below:

NH4NO3 —> N2 + 1/2O2 + 2H2O

Now, multiply through by 2 to clear the fraction as shown below

2NH4NO3 —> 2N2 + O2 + 4H2O

Now the equation is balanced

3 0
3 years ago
Gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If of water is produced from
krek1111 [17]

The given question is incomplete. The complete question is :

Gaseous butane reacts with gaseous oxygen gas  to produce gaseous carbon dioxide and gaseous water . If 1.31g of water is produced from the reaction of 4.65g of butane and 10.8g of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.

Answer: 28.0 %

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of butane}=\frac{4.65g}{58g/mol}=0.080moles

\text{Moles of oxygen}=\frac{10.8g}{32g/mol}=0.34moles

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

According to stoichiometry :

13 moles of O_2 require 2 moles of butane

Thus 0.34 moles of O_2 will require=\frac{2}{13}\times 0.34=0.052moles  of butane

Thus O_2 is the limiting reagent as it limits the formation of product and butane is the excess reagent.

As 13 moles of O_2 give = 10 moles of H_2O

Thus 0.34 moles of O_2 give =\frac{10}{13}\times 0.34=0.26moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=0.26moles\times 18g/mol=4.68g

{\text {percentage yield}}=\frac{\text {Experimental yield}}{\text {Theoretical yield}}\times 100\%

{\text {percentage yield}}=\frac{1.31g}{4.68g}\times 100\%=28.0\%

The percent yield of water is 28.0 %

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4 years ago
Balancing chemical equations<br> (8 questions)
sweet [91]
Sorry it’s messy, hope this helps :]

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2 years ago
Define fundamental quantities.​
Bad White [126]

Answer:

In physics, there are seven fundamental physical quantities that are measured in base or physical fundamental units: length, mass, time, electric current temperature, amount of substance, and luminous intensity.

Explanation:

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3 years ago
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