Answer:
Energy needed = 54.02 J
Explanation:
the Energy in an elastic spring from hookes law is given as
F= ke , therefore the energy (E) is
E =
K = 19.5 N/cm
e = 1.39cm
E = x 19.5 x 1.39
E = 13.55 J
The energy to stretch the spring for 6.93cm is
E = x 19.5 x 6.93
E = 67.57 J
The more energy needed for the further stretch is
67.57 - 13.55
Energy needed = 54.02 J
1 × 3 = 3
<h3>step 3. find 36 divided by 2</h3>36 ÷ 2 = 18
<h3>step 4. add the values together</h3>18 + 3 = 21
<h3>step 5. find 14 times 3</h3>14 × 3 = 42 <em>you can also do 7 × 6 and will get the same result because 7 is half of 14 and 3 is half of 6</em>
<h3>step 6. add what is outside the parentheses</h3>21 + 42 = 63
<h3>step 7. divide by 6</h3>63 ÷ 6 = 10.5 10 remainder of 3 <em>remainder means left over</em>
<em />
Answer:
a)
b) west end of the bar is positive.
Explanation:
Given:
(a)
The magnitude of the horizontal component of the Earth's magnetic field(B):
We know:
(b)
Using Fleming's left hand rule we determine that the current is flowing towards east end of the bar i.e. west end of the bar is positive.