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2 years ago

Jade recorded how many characters she used in each of her 999 most recent text messages. Here's a histogram showing her data:

Mathematics

1 answer:

Evgesh-ka [11]2 years ago

8 0

Using it's concept, the interval that contains the median number of characters is: 30 - 40.

<h3>What does the histogram shows?</h3>

The problem is incomplete, but researching it on a search engine, we have that:

She had 3 messages between 0 and 10 characters.

She had 1 message between 10 and 20 characters.

She had 1 message between 20 and 30 characters.

She had 2 messages between 30 and 40 characters.

She had 1 message between 60 and 70 characters.

She had 1 message between 100 and 120 characters.

<h3>What is the median of a data-set?</h3>

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.

In this problem, we have a data-set of 9 elements, hence the median is the 5th element, as:

The first half is composed by the first four elements.

The second half is composed by the last four elements.

The fifth element of the histogram is in the interval 30-40, which is the interval that contains the median.

More can be learned about the median of a data-set at brainly.com/question/23923146

#SPJ1

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How would I graph y = 2/3x + 1 ?

cestrela7 [59]

Answer:

Shown below

Step-by-step explanation:

you would start with positive one on the y axis then go up two and to the right 3 and continue it

Des.mos.com is also a graphing calculator that helps with this!

7 0

3 years ago

Sherrod and Kamar are planning to drive at most 900 miles road trip. Sherrod drives at 60 miles per hour, and Kamar at 50 miles

Allushta [10]

The inequality gives the total expected journey from the road trip, such that the time during which Sherrod and Kamar drives is known.

a. The inequality that represents the miles that Sherrod and Kamar drives is; <u>x + y ≤ 900</u>

b. Two possible combination of <em>x</em> and <em>y</em> are; <u>(600, 300) and (300, 600)</u>

Reasons:

a. The distance distance Sherrod and Kamar plan to drive ≤ 900 miles

Sherrod's speed = 60 mph

Kamar's speed = 50 mph

The distance Sherrod drives = x

The distance Kamar drives = y

a. The miles driven by Sherrod and Kamar is given by the inequality;

<u>x + y ≤ 900</u>

b. Two possible combinations are;

First possible combination;

Sherrod drives for 10 hours, which gives;

Distance Sherrod drives = 60 mph × 10 hour = 600 miles

Kamar drives for 900 miles - 600 miles = 300 miles

Which gives;

Sherrod drives for 600 miles and Kamar drives for 300 miles

<u>First combination; (600, 300)</u>

Second possible combination;

The second possible combination is Sherrod drives for 300 miles and Kamar drives for 600 miles

<u>Second combination; (300, 600)</u>

Learn more about inequalities here:

brainly.com/question/22976364

6 0

2 years ago

Jason had one hundred fifty-nine dollars to spend six books.After buying them he had fifteen dollars.How much did each book cost

Alla [95]

Answer:

11.5

Step-by-step explanation:

Divide: 159:6-15

Calculate: 26.5-15

\\11.5//

6 0

3 years ago

Read 2 more answers

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.75$

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581$

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$