Answer:
35 ways
Step-by-step explanation:
Alex has 9 friends and wants to invite 5 friends. Since Alex requires two of his friends who are twins to come together to his birthday party, since the two of them form a group, the number of ways we can select the two of them to form a group of two is ²C₂ = 1 way.
Since we have removed two out of the nine friends, we are left with 7 friends. Also, two friends are already selected, so we are left with space for 3 friends. So, the number of ways we can select a group of 3 friends out of 7 is ⁷C₃ = 7 × 6 × 5/3! = 35 ways.
So, the total number ways we can select 5 friend out of 9 to party come to the birthday include two friends is ²C₂ × ⁷C₃ = 1 × 35 = 35 ways
Well basically you just have to chose a number of sides for the side length of the square to be and move those many places to get another vertex of the square. For example if we have (-2,3) and we choose the side lengths to be 4 units than you could move 4 places up, down, left, or right to get the other vertices for the square
Hope that helps :)
Answer: good luck
Step-by-step explanation:Step 1) Because the first equation is already solved for
y
we can substitute
3
x
+
8
for
y
in the second equation and solve for
x
:
8
x
+
4
y
=
12
becomes:
8
x
+
4
(
3
x
+
8
)
=
12
8
x
+
(
4
⋅
3
x
)
+
(
4
⋅
8
)
=
12
8
x
+
12
x
+
32
=
12
(
8
+
12
)
x
+
32
=
12
20
x
+
32
=
12
20
x
+
32
−
32
=
12
−
32
20
x
+
0
=
−
20
20
x
=
−
20
20
x
20
=
−
20
20
20
x
20
=
−
1
x
=
−
1
Step 2) Substitute
−
1
for
x
in the first equation and calculate
y
:
y
=
3
x
+
8
becomes:
y
=
(
3
⋅
−
1
)
+
8
y
=
−
3
+
8
y
=
5
The solution is:
x
=
−
1
and
y
=
5
or
(
−
1
,
5
)
All the sides of a square must equal 90 degrees. With that information, we can determine that corner C is 45 degrees. We can tell that the line that reaches corner C divides the angle by 2. So 90/2=45.
We also know
N and n+2 because if n=1 then you do 1+2 and that equals 3. So then you have 1,3
