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2 years ago

A(n) _____ is a line drawn around an element, enclosing the element content, padding, and border spaces.

Chemistry

1 answer:

velikii [3]2 years ago

5 0

An outline is a line drawn around an element, enclosing the element content, padding, and border spaces.

A form or figure's outline is defined by a line or combination of lines. The lines restrict the shape, isolating it inside the composition or the area. The shapes are created by the outlines.

The phrase "outline" in art refers to the lines, real or apparent, that define or confine a figure (or shape) within the field of vision, with the total number of these lines defining the contour of the figure.

An item is depicted by lines of contour without shade in an outline sketch or drawing, leaving out internal detail. A variety of markers are used to transform an object's seeming edge into a useful reference on paper.

To learn more about drawing refer to:

brainly.com/question/12100213

#SPJ4

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What are some main points about star formation

AysviL [449]

Explanation:

A Giant Gas Cloud. A star begins life as a large cloud of gas.

A Protostar Is a Baby Star.

The T-Tauri Phase.

Main Sequence Stars.

Expansion into Red Giant.

Fusion of Heavier Elements.

Supernovae and Planetary Nebulae.

6 0

3 years ago

We know that one mole of Oxygen gas contains two moles of O atoms (remember that O is a diatomic element in nature and is writte

tatiyna

Answer:

12.4 × 10∧3 atoms

Explanation:

Given data:

moles of oxygen molecule= 1.0000 x 10-20 mol

atoms =?

Solution:

32 g O2 = 1 mol = 6.02 × 10∧23

1.0000 x 10∧-20 mol × 6.02 × 10∧23 × 2 = 12.4 × 10∧3 atoms

6 0

4 years ago

The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 8.600 g C6H6 is burned and the heat pr

jenyasd209 [6]

Answer : The final temperature of the water is, $22.5166^oC$

Explanation : Given,

Mass of benzene = 8.600 g

Molar mass of benzene = 78 g/mole

First we have to calculate the moles of benzene.

$\text{Moles of benzene}=\frac{\text{Mass of benzene}}{\text{Molar mass of benzene}}=\frac{8.600g}{78g/mol}=0.1103mole$

Now we have to calculate the energy of combustion.

The given balanced chemical reaction is:

$2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ$

According to reaction,

As, 2 moles of benzene gives 6542 kJ of energy on combustion.

So, 0.1103 mole of benzene gives $\frac{6542 kJ}{2}\times 0.1103=360.7913kJ$ of energy on combustion.

Now we have to calculate the final temperature of the water.

Formula used : $q_w=m_w\times c_w\times \Delta T=m_w\times c_w\times (T_{final}-T_{initial})$

where,

$q_w$ = heat released = 360.7913 kJ = 36079.13 J

$m_w$ = mass of water = 5691 g

$c_w$ = specific heat of water= $4.18J/g^oC$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $21^oC$

Now put all the given values in the above formula, we get:

$36079.13J=5691g\times 4.18J/g^oC\times (T_{final}-21^oC)$

$T_{final}=22.5166^oC$

Therefore, the final temperature of the water is, $22.5166^oC$

8 0

4 years ago

How many milliliters of a 0.275 M NaOH solution is required to react with 0.450 L of CO2 gas

padilas [110]

Volume of NaOH required to react = 145.5 ml

<h3>Further explanation</h3>

Reaction

CO₂(g) + 2 NaOH(aq) ⇒Na₂CO₃(aq) + H₂O(l)

The volume of CO₂ : 0.45 L

mol CO₂ at STP (O C, 1 atm) ⇒ at STP 1 mol gas 22.4 L :

$\tt mol~CO_2=\dfrac{0.45}{22.4}=0.02$

From the equation, the mol ratio of CO₂ : NaOH = 1 : 2, so mol NaOH :

$\tt mol~NaOH=\dfrac{2}{1}\times 0.02=0.04$

Then volume of NaOH :

$\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.04}{0.275}\\\\V=0.1455~L\rightarrow 145.5~mL$

5 0

3 years ago

Whoever answers correct I’ll give you Britney Brainly

Daniel [21]

the correct answer is thermal or light

5 0

3 years ago