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eimsori [14]
3 years ago
13

Please help me with chemistry!! with explanation so i can understand and further the knowledge

Chemistry
1 answer:
iren [92.7K]3 years ago
6 0
Density= mass/volume aluminum can= 174 •g/ 4 • cm ^3. =2.76•g•cm ^-3
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The seasonal shifts of earths planetary wind and moisture belts are due to changes in the
ANEK [815]

The seasonal shifts of Earth's planetary wind and moisture belts are due to changes in the latitude that receives the sun's vertical rays.

<h3>What is the latitude?</h3>

The latitude refers to the specific geographic coordinates at some point of the Earth in relation to the Equator line.

Latitude and longitude are geographic coordinates that allow to localize a specific point in the world by using the center of the Earth's planet as point of origin.

The amount of sun rays received by a given latitude largely depends on the season since the Earth's planet has a light inclination that alter this amount of radiation.

In conclusion, the seasonal shifts are due to changes in the latitude that receives the sun's vertical rays.

Learn more about the latitude and radiation here:

brainly.com/question/3005929

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7 0
2 years ago
The atomic mass for Mg is<br> O 55<br> O 54<br> O 60
Ivenika [448]
The answer is 60 (C)
3 0
4 years ago
A piece of stainless steel with a mass of 25.0 g has a temperature of 50.0°
Darina [25.2K]

Answer:

0.336 J/g/C

Explanation:

Recall the equation for specific heat:

q = mcΔT

1250 = 25 x c x 149

c = 0.336

5 0
3 years ago
Arya drops a small sample of brown iodine into a beaker of water.
kiruha [24]
A the iodine spreads evenly throughout the water
8 0
4 years ago
Calculate the value of the diffusion coefficient D (in m2/s) at 547°C for the diffusion of some species in a metal; assume that
svetlana [45]

Answer : The value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

Explanation :

Formula used :

D=D_o\times \exp \left(-\frac{Q_d}{RT}\right )

where,

D = diffusion coefficient = ?

D_o = 5.6\times 10^{-5}m^2/s

Q_d = 177kJ/mol

R = gas constant = 8.314 J/mol.K

T = temperature = 547^oC=273+547=820K

Now put all the given values in the above formula, we get:

D=5.6\times 10^{-5}m^2/s\times \exp \left(-\frac{177kJ/mol}{(8.314J/mol.K)\times (820K)}\right )

D=2.97\times 10^{-16}m^2/s

Thus, the value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

6 0
3 years ago
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