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2 years ago

What is the mass of 2.1 moles of the hydrate Nickel (II) carbonate pentahydrate (NiCO3 x 5H2O)?

Chemistry

1 answer:

kifflom [539]2 years ago

4 0

The mass of 2.1 moles of the hydrate Nickel (II) carbonate pentahydrate NiCO3 x 5H2O 773.5 grams.

<h3>What are moles?</h3>

Mole is the smallest particle of atom which is equal to the Avogadro's number which is 2.303 × 10²³moles of an atom and can be calculated by,

number of moles = mass of mole / molar mass of the mole.

mass = 2.1 moles

molar mass of NiCO3 x 5H2O = 368.38

Substituting the value in the formula,

2.1 mole = mass of mole / 368.38

mass of mole = 773.59 grams.

Therefore, mass of 2.1 moles of the hydrate Nickel (II) carbonate pentahydrate NiCO3 x 5H2O 773.5 grams.

Learn more about moles, here:

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What is the pH of a 2.5 x 10-5 M solution of HCI?

aalyn [17]

Answer:

The pH of the solution is 4.60.

Explanation:

The pH gives us an idea of the acidity or basicity of a solution. More precisely, it indicates the concentration of H30 + ions present in said solution. The pH scale ranges from 0 to 14: from 0 to 7 corresponds to acid solutions, 7 neutral solutions and between 7 and 14 basic solutions. It is calculated as:

pH = -log (H30 +)

pH= -log (2,5 x 10-5)

pH=4.60

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3 years ago

1.- Ilumina de amarillo los verbos en pretérito y de verde los verbos en copretérito.

ivanzaharov [21]

Answer:

Pretérito (Pretérito perfecto):

estiró, sudó, peleó, compartí

Copretérito (Pretérito imperfecto):

saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian

Explanation:

Los verbos en pretérito, también llamado pretérito perfecto, son los siguientes:

estiró, sudó, peleó, compartí

Como se aprecia, los verbos conjugados en pretérito perfecto terminan la última sílaba en vocal con acento, es decir, -á, -é, -í u -ó.

Los verbos en copretérito, también llamado pretérito imperfecto, son los siguientes:

saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian

Como se aprecia, los verbos conjugados en pretérito imperfecto terminan la última sílaba en -ía, ías, -ían, -aba, -abas o -aban.

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3 years ago

A chemistry graduate student is given 125.mL of a 1.00M benzoic acid HC6H5CO2 solution. Benzoic acid is a weak acid with =Ka×6.3

lubasha [3.4K]

Answer:

53.9 g

Explanation:

When talking about buffers is very common the problem involves the use of the Henderson Hasselbach formula:

pH = pKa + log [A⁻]/[HA]

where [A⁻] is the concentration of the conjugate base of the weak acid HA, and [HA] is the concentration of the weak acid.

We can calculate pKₐ from the given kₐ ( pKₐ = - log Kₐ ), and from there obtain the ratio [A⁻]/HA].

Since we know the concentration of HC6H5CO2 and the volume of solution, the moles and mass of KC6H5CO2 can be determined.

So,

4.63 = - log ( 6.3 x 10⁻⁵ ) + log [A⁻]/[HA] = - (-4.20 ) + log [A⁻]/[HA]

⇒ log [A⁻]/[HA] = 4.63 - 4.20 = log [A⁻]/[HA]

0.43 = log [A⁻]/[HA]

taking antilogs to both sides of this equation:

10^0.43 = [A⁻]/[HA] = 2.69

[A⁻]/ 1.00 M = 2.69 ⇒ [A⁻] = 2.69 M

Molarity is moles per liter of solution, so we can calculate how many moles of C6H5CO2⁻ the student needs to dissolve in 125. mL ( 0.125 L ) of a 2.69 M solution:

( 2.69 mol C6H5CO2⁻ / 1L ) x 0.125 L = 0.34 mol C6H5CO2⁻

The mass will be obtained by multiplying 0.34 mol times molecular weight for KC6H5CO2 ( 160.21 g/mol ):

0.34 mol x 160.21 g/mol = 53.9 g

3 0

3 years ago

The following chemical reactants produce the ester ethyl ethanoate (C4H8O2): C2H6O + CH3COOH What type of reaction occurs to mak

nydimaria [60]

Answer:

Esterification reaction

Explanation:

An esterification reaction is an organic reaction involving an organic acid and an alkanol to give an ester or an ethanoate and water

Like the name suggests, an ester is the product formed in an esterification reaction alongside water. It is like a neutralization reaction but this time it solely contains organic molecules. These molecules react with each other to give rise to another organic molecule which is a member of a different homologous series.

Practically, to form ethyl ethanoate, ethanoic acid react with ethanol in the presence of concentrated sulphuric acid which catalyses the reaction.

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