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Katarina [22]
3 years ago
13

Is it possible for a diprotic acid to have Ka1?

Chemistry
1 answer:
Masja [62]3 years ago
4 0

Answer:

Yes, it is possible.

Explanation:

A diprotic acid is an acid that can release two protons. That's why it is called diprotic.

Monoprotic → Release one proton, for example Formic acid HCOOH

Triprotic → Releases three protons, for example H₃PO₄

Polyprotic → Release many protons, for example EDTA

it is a weak acid.

In the first equilibrum, it release proton, and the second is released in the second equilibrium. So the first equilibrium will have a Ka1

H₂A  +  H₂O  ⇄  H₃O⁺  +  HA⁻                Ka₁

HA⁻  +  H₂O  ⇄  H₃O⁺  +  A⁻²               Ka₂

The HA⁻ will work as an amphoterous because, it can be a base or an acid, according to this:

HA⁻   +  H₂O  ⇄  H₃O⁺   + A⁻²      Ka₂

HA⁻   +  H₂O  ⇄  OH⁻   + H₂A       Kb₂

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Answer:

4.68x10²⁵ ions of Na⁺

Explanation:

First of all, we dissociate the salt:

NaCl(aq) → Na⁺(aq) + Cl⁻(aq)

An aqueous solution of NaCl dissociates in chlorides anions and sodium cations. Ratio is 1:1, per 1 mol of NaCl, we have 1 mol of Na⁺

We determine the moles of salt: 4543.3 g . 1mol / 58.45 g = 77.7 moles

77.7 moles are the amount of NaCl, therefore we have 77.7 moles of Na⁺.

We count the ions:

1 mol fo Na⁺ has 6.02x10²³ ions

77.7 moles of Na⁺ must have (77.7 . 6.02x10²³) / 1 = 4.68x10²⁵ ions of Na⁺

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