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Katarina [22]
3 years ago
13

Is it possible for a diprotic acid to have Ka1?

Chemistry
1 answer:
Masja [62]3 years ago
4 0

Answer:

Yes, it is possible.

Explanation:

A diprotic acid is an acid that can release two protons. That's why it is called diprotic.

Monoprotic → Release one proton, for example Formic acid HCOOH

Triprotic → Releases three protons, for example H₃PO₄

Polyprotic → Release many protons, for example EDTA

it is a weak acid.

In the first equilibrum, it release proton, and the second is released in the second equilibrium. So the first equilibrium will have a Ka1

H₂A  +  H₂O  ⇄  H₃O⁺  +  HA⁻                Ka₁

HA⁻  +  H₂O  ⇄  H₃O⁺  +  A⁻²               Ka₂

The HA⁻ will work as an amphoterous because, it can be a base or an acid, according to this:

HA⁻   +  H₂O  ⇄  H₃O⁺   + A⁻²      Ka₂

HA⁻   +  H₂O  ⇄  OH⁻   + H₂A       Kb₂

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attashe74 [19]

Answer:

Some materials let electricity pass through them easily. These materials are known as electrical conductors. Many metals, such as copper, iron and steel, are good electrical conductors.

I hope it's helpful!

3 0
3 years ago
Be sure to answer all parts. Solving the Rydberg equation for energy change gives ΔE = R[infinity]hc [ 1 n12 − 1 n22 ] where the
icang [17]

Answer:

Explanation:

Utilizing Rydber's  equation:

ΔE = Z²Rh ( 1/n₁² - 1/n₂²) and substituting the values given ( using the Rydbers constant value in Joules ), we have

n=1 to n= infinity

ΔE = 3² x (1/1² - 0) x 2.18 x 10⁻^18 J = 2.0 x 10⁻¹⁷ J      (1/infinity is zero)

n= 3 to n= infinity

ΔE = 3² x (1/3² - 0) x 2.18 x 10⁻^18 J = 2.28 x 10^-18 J

b.  The wavelength of the emitted can be obtained again by using Rydberg's equation but this time use the constant value 1.097 x 10⁷ m⁻¹ given in the problem .

1/λ = Z²Rh (1/n₁² - 1/n₂²) 10 ⁻¹ = 3² x 1.097 x 10⁷ m⁻¹ x (1/1² - 1/3²) m⁻¹

1/λ =8.8 x 10⁷ m⁻¹ ⇒  λ =1.1 x 10^-8 m

λ = 1.1 x 10^-8 m x 1 x 10⁹ nm/m = 11 nm

7 0
3 years ago
Read 2 more answers
How many electrons can the third energy level hold?
dusya [7]
I believe the answer is 18. 
6 0
4 years ago
When 0.422g of phosphorus is burned, 0.967g of a white oxide is obtained.
nata0808 [166]
Moles = mass / molar mass 

<span>moles P = 0.422 g / 30.97 g/mol = 0.01363 mol </span>
<span>moles O = (0.967 g - 0.422g) / 16.00 g/mol = 0.03406 moles </span>

<span>So ratio moles P : moles O </span>
<span>= 0.01363 mol : 0.03406 mol </span>

<span>Divide each number in the ratio by the smallest number </span>

<span>(0.01363 / 0.01363) : (0.03406 / 0.01363) </span>
<span>= 1 : 2.5 </span>

<span>The empirical formula needs to be the smallest whole number ratio of atoms in the molecules. Since you have a non-whole number, multiply the ratio by the smallest number needed to make both number whole numbers. In this case x 2 </span>

<span>2 x (1 : 2.5) </span>
<span>= 2 : 5 </span>
5 0
3 years ago
Read 2 more answers
What is the formula for calcium chloride?<br><br><br> Ca2Cl<br><br> CaCl<br><br> CaCl2<br><br> CaCl3
djyliett [7]
<em>Hello there, and thank you for asking your question here on brainly.

The answer to this is Answer choice C: CaCl2

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8 0
4 years ago
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