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olganol [36]
2 years ago
6

The center on your school’s basketball team is 6 ft 10 in tall. How tall is the player in millimeters (mm)?

Chemistry
1 answer:
svp [43]2 years ago
5 0

The answer is 6 ft 10 inches in millimeters (mm) is 0.833 ft.

Given,

The center of the school's basketball team is 6 ft 10 inches tall.

We have to convert the height of the player from feet and inches to feet.

Using the conversion factor,

1 ft = 12 inches

or, 12inches/ 1 ft

Converting 6ft 10 inches to ft, we get;

10 inches × 1 ft/ 12inches

= 0.833 ft

Therefore 6 ft 10 inches in millimeters (mm) is 0.833 ft.

Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.

To learn more about Millimeter and Unit conversions, visit: brainly.com/question/26371870

#SPJ4

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If 1.546 g of copper was used by a student at the start of the lab, and 0.732 g of copper were obtained at
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Answer: Percent recovery is 47.34 %

Explanation:

Percent yield is defined as the ratio of experimental yiled to theoretical yield in terms of percentage.

{\text{ percent yield}}=\frac{\text{amount recovered}}{\text{total amount}}\times 100

Putting in the values we get:

{\text{ percent yield}}=\frac{0.732}{1.546}\times 100=47.34\%

Therefore, the percent recovery is 47.34 %

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Which type of molecule is shown below?
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The answer is A. It is an alkyn. There is a triple bond
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A rock contains 0.623 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the
maxonik [38]

Answer:

t = 3,496x10⁹ years

Explanation:

The decay of ²³⁸U is:

²³⁸U → ²⁰⁶Pb + 8He + 6e⁻

Moles of ²⁰⁶Pb presents in 0,623mg are:

0,623x10⁻³g×(1mol / 206g) = 3,02x10⁻⁶ moles of ²⁰⁶Pb.

These moles are equals to moles of ²³⁸U before decay, that means, 3,02x10⁻⁶ moles²³⁸U

In grams:

3,02x10⁻⁶ moles²³⁸U× (238g / 1mol) = 7,20x10⁻⁴ g ²³⁸U = 0,720 mg²³⁸U

That means initial ²³⁸U was 1,000mg + 0,720mg =<em> 1,720mg</em>

Applying the formula:

ln (N₀/N) t₁₂ = t ln2

Where N₀ is initial amount of uranium (1,720mg), N is concentration of uranium (1,000mg),  half-life time is a constant (t₁₂= 4,468x10⁹ years) and t is the time transcurred for the reaction. Replacing:

ln(1,720/1)*4,468x10⁹ years = t ln2

<em>t = 3,496x10⁹ years</em>

<em></em>

I hope it helps!

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3 years ago
The specific heat of a substance is the heat that must be absorbed to increase the temperature of 1 gram of a substance by 1 deg
Vlad1618 [11]

Answer:

True.

Explanation:

Specific heat is the amount of heat required to raise one gram of a particular substance by one degree Celsius or Kelvin.

Formula for calculating specific heat is the amount of heat absorbed or released = mass x specific heat x change in temperature.

= m * Cp * delta T

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I think thee answer is C


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