Answer:
a) 4.2m/s
b) 5.0m/s
Explanation:
This problem is solved using the principle of conservation of linear momentum which states that in a closed system of colliding bodies, the sum of the total momenta before collision is equal to the sum of the total momenta after collision.
The problem is also an illustration of elastic collision where there is no loss in kinetic energy.
Equation (1) is a mathematical representation of the the principle of conservation of linear momentum for two colliding bodies of masses 
and 
whose respective velocities before collision are 
and 
;
where 
and 
are their respective velocities after collision.
Given;
Note that =0 because the second mass was at rest before the collision.
Also, since the two masses are equal, we can say that 
so that equation (1) is reduced as follows;
m cancels out of both sides of equation (2), and we obtain the following;
a) When 
, we obtain the following by equation(3)
b) As stops moving 
, therefore,
Answer:
83.3 kHz
Explanation:
The frequency of a waveform is equal to the reciprocal of its period:
where
f is the frequency
T is the period
In this problem, we have
so, the frequency of the waveform is
And by converting into kiloHertz,
Answer:
58.33 Hz
175 Hz
291.67 Hz
Explanation:
L = Length of tube = 1.5 m
v = Speed of sound in air = 350 m/s
The first resonant frequency is given by
The first resonant frequency is 58.33 Hz
The second resonant frequency is given by
The first resonant frequency is 175 Hz
The third resonant frequency is given by
The first resonant frequency is 291.67 Hz
Answer:
4 m/s²
Explanation:
The formula used here:
F = ma
F is force (80 N)
m is mass (20 kg)
a is acceleration
Since we need to calculate acceleration we will arrange the formula:
a = F ÷ m
Now substitute the values and solve
a = 80 ÷ 20
a = 4
The proper unit for this acceleration is m/s²
So the object accelerates at 4 m/s²
