The driver or a sports car traveling at 10 m/s steps down hard on the accelerator for 5 seconds. If they accelerate at a rate of 0.25 m/s2, what is the displacement of the car?
1 answer:
Answer:
53.125m
Explanation:
The displacement of the car, denoted by S, can be calculated using the formula:
S = ut + 1/2at²
Where;
u = initial velocity/speed (m/s)
t = time (s)
a = acceleration (m/s²)
According to the information provided in this question, u = 10m/s, t = 5s, a = 0.25m/s², S = ?
S = ut + 1/2at²
S = (10 × 5) + 1/2 (0.25 × 5²)
S = 50 + 1/2 (0.25 × 25)
S = 50 + 1/2(6.25)
S = 50 + 3.125
S = 53.125m
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