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1 year ago

Doug is doing work. without knowing exactly what he is doing, which can be said about the work he is doing?

Physics

1 answer:

Ostrovityanka [42]1 year ago

3 0

Energy is transferred.

Every time labour is performed, energy is transmitted, as shown by the definition of work in physics. Work is the result of the displacement's magnitude and the component of force acting in that direction.

What are 3 types of work done?

Positive
Negative
Zero work done.

Work is the result of force and distance, or the force exerted over a specific distance. In other words, Work = Force x Distance.

Joules are used to measure work.

1. Positive Work: Positive work is when a force moves an object in that direction. The motion of a ball descending toward the earth while it is displaced in the direction of the force of gravity is an illustration of this type of labour.

2. Negative Work: The work is said to be negative if the force and the displacement are in the opposing directions. For instance, if a ball is thrown high, its displacement will also be upwards, while the force from the earth's gravity will be downward.

3. Zero Work: When the force and displacement directions are parallel to one another, there is no work done on the item by the force.

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A third baseman makes a throw to first base 40.5 m away. The ball leaves his hand with a speed of 30.0 m/s at a height of 1.4 m

Ugo [173]

Answer:

When the ball goes to first base it will be 4.23 m high.

Explanation:

Horizontal velocity = 30 cos17.3 = 28.64 m/s

Horizontal displacement = 40.5 m

Time

$t=\frac{40.5}{28.64}=1.41s$

Time to reach the goal posts 40.5 m away = 1.41 seconds

Vertical velocity = 30 sin17.3 = 8.92 m/s

Time to reach the goal posts 40.5 m away = 1.41 seconds

Acceleration = -9.81m/s²

Substituting in s = ut + 0.5at²

s = 8.92 x 1.41 - 0.5 x 9.81 x 1.41²= 2.83 m

Height of throw = 1.4 m

Height traveled by ball = 2.83 m

Total height = 2.83 + 1.4 = 4.23 m

When the ball goes to first base it will be 4.23 m high.

8 0

3 years ago

A 50.0 kg crate is pulled 375 N of force applied to a rope. The crate slides without friction.

LUCKY_DIMON [66]

Hi there!

We can use the work-energy theorem to solve.

Recall that:

$\large\boxed{W = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2}$

The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:

$W = \frac{1}{2}(50)(5.61^2) = 786.8025 J$

Now, we can define work:

$\large\boxed{W = Fdcos\theta}}$

Now, plug in the values:

$786.8025 = Fdcos\theta\\\\786.8025 = (375)(3.07)cos\theta$

Solve for theta:

$cos\theta = .6834\\\theta = cos^{-1}(.6834) = \boxed{46.887^o}$

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2 years ago

Two identical stones, A and B, are thrown from a cliff from the same height and with the same initial speed. Stone A is thrown v

Taya2010 [7]

Answer:

Option A

Explanation:

This can be explained based on the conservation of energy.

The total mechanical energy of the system remain constant in the absence of any external force. Also, the total mechanical energy of the system is the sum of the potential energy and the kinetic energy associated with the system.

In case of two stones thrown from a cliff one vertically downwards the other vertically upwards, the overall gravitational potential energy remain same for the two stones as the displacement of the stones is same.

Therefore the kinetic energy and hence the speed of the two stones should also be same in order for the mechanical energy to remain conserved.

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3 years ago

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1 year ago

During an earthquake, where is the greatest motion felt on the surface?

dalvyx [7]

That would be the epicenter.

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