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1 year ago

Doug is doing work. without knowing exactly what he is doing, which can be said about the work he is doing?

Physics

1 answer:

Ostrovityanka [42]1 year ago

3 0

Energy is transferred.

Every time labour is performed, energy is transmitted, as shown by the definition of work in physics. Work is the result of the displacement's magnitude and the component of force acting in that direction.

What are 3 types of work done?

Positive
Negative
Zero work done.

Work is the result of force and distance, or the force exerted over a specific distance. In other words, Work = Force x Distance.

Joules are used to measure work.

1. Positive Work: Positive work is when a force moves an object in that direction. The motion of a ball descending toward the earth while it is displaced in the direction of the force of gravity is an illustration of this type of labour.

2. Negative Work: The work is said to be negative if the force and the displacement are in the opposing directions. For instance, if a ball is thrown high, its displacement will also be upwards, while the force from the earth's gravity will be downward.

3. Zero Work: When the force and displacement directions are parallel to one another, there is no work done on the item by the force.

to learn more about Work go to - brainly.com/question/6535839

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Complete the equation to show the radioactive decay of carbon-14 to nitrogen-14

blsea [12.9K]

Answer:

The beta decay takes place.

Explanation:

The reaction of radioactivity of carbon 14 to nitrogen 14 is

There is a beta decay.

The reaction is

$C_{6}^{14}\rightarrow N_{7}^{14}+\beta _{-1}^{0}+ energy$

Here some energy is released in form of neutrino.

7 0

2 years ago

Which of the following is NOT a example

solmaris [256]

Answer:

B. a piece of paper being torn

Explanation:

A chemical change is one that cannot be reversed. This means the original properties of the substance or object cannot be restored.

If you cook a raw egg, it would turn into a boiled egg (or a poached egg, however it is being cooked). The reaction is irreversible, so you cannot turn the cooked egg back into a raw egg - it is basically impossible to 'uncook' an already cooked egg.

When you toast a piece of bread, it turns into toast. You can't 'untoast' it back into bread. The chemical changes have already occurred and cannot be undone.

If you tear a piece of paper, it is still paper. You are only ripping it, not changing anything about it. You could simply tape the torn bit back to the original bit, or glue it - either way, it is still paper and nothing has occurred to drastically change the physical state of it.

Therefore, B is not a chemical change.

5 0

2 years ago

A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear

Talja [164]

Answer:

70.07 Hz

Explanation:

Since the sound is moving away from the observer then

$f_o = f_s\frac {(v+vs)}{v}$ and $f_o = f_s\frac {(v-vs)}{v}$ when moving towards observer

With $f_o$ of 76 then taking speed in air as 343 m/s we have

$76 = f_s\times\frac {(343-vs)}{343}$

$f_s=\frac {343\times 76}{343-v_s}$

Similarly, with $f_o$ of 65 we have

$65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}$

Now

$f_s=\frac {343\times 65}{343+v_s}=\frac {343\times 76}{343-v_s}$

v_s=27.76 m/s

Substituting the above into any of the first two equations then we obtain

$f_s=70.07 Hz$

4 0

3 years ago

A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.2 rad/s in 3.07 s. (a) f

Hitman42 [59]

(a) The angular acceleration of the wheel is given by
$\alpha = \frac{\omega_f - \omega_i }{t}$
where $\omega_i$ and $\omega_f$ are the initial and final angular speed of the wheel, and t the time.

In our problem, the initial angular speed is zero (the wheel starts from rest), so the angular acceleration is
$\alpha = \frac{(11.2 rad/s) - 0}{3.07 s} =3.65 rad/s^2$

(b) The wheel is moving by uniformly rotational accelerated motion, so the angle it covered after a time t is given by
$\theta (t) = \omega_i t + \frac{1}{2} \alpha t^2$
where $\omega_i = 0$ is the initial angular speed. So, the angle covered after a time t=3.07 s is
$\theta= \frac{1}{2} \alpha t^2 = \frac{1}{2}(3.65 rad/s^2)(3.07 s)^2 = 17.2 rad$

6 0

2 years ago

Did i get any of these answers right if not what do i have to change

gregori [183]

Answer:

You got them right

8 0

3 years ago