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Harlamova29_29 [7]
3 years ago
14

The origins of Yoga can be traced back to which ancient scholar?​

Physics
2 answers:
Mashcka [7]3 years ago
5 0

Answer:

Rig Veda

Explanation:

faust18 [17]3 years ago
4 0

Answer:

it can be traced to rig veda

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To store stacks of clean plates, a cafeteria uses a closed cart with a spring-loaded shelf inside. Customers can take plates off
ruslelena [56]

The answer for the following problem is mentioned below.

The option for the question is "A" approximately.

  • <u><em>Therefore the elastic potential energy of the string is 20 J.</em></u>

Explanation:

Given:

Spring constant (k) = 240 N/m

amount of the compression (x) = 0.40 m

To calculate:

Elastic potential energy (E)

We know;

<em>According to the formula;</em>

    E = \frac{1}{2} × k × x × x

   <u>E = </u>\frac{1}{2}<u> × k ×(x)²</u>

where;

E represents the elastic potential energy

K represents the spring constant

x represents amount of the compression in the string

So therefore,

Substituting the values in the above formula;

      E = \frac{1}{2} × 240 × (0.40)²

      E =  \frac{1}{2} × 240 × 0.16

      E =  \frac{1}{2} × 38.4

      E = 19.2 J or approximately 20 J

<u><em>Therefore the elastic potential energy of the string is 20 J.</em></u>

5 0
3 years ago
Joseph is sitting in the family van. His mother is driving him from their house to the library. Joseph waves as he passes his fr
CaHeK987 [17]
The correct answer is the family van. Joseph is sitting inside of it and it doesn't move relative to him. The van is moving and everything outside the van is moving relative to Joseph so the library, Maria and <span>Jane's house are moving relative to him.</span>
6 0
3 years ago
In which of these samples do the molecules mist likely have the least kinetic energy
KiRa [710]
Provide the examples again, no samples are presents.
8 0
3 years ago
Titanium metal requires a photon with a minimum energy of 6.94×10−19J to emit electrons. If titanium is irradiated with light of
butalik [34]

Answer:

a) 1.59(10)^{-19} J

b) 2.34(10)^{12} electrons

Explanation:

The photoelectric effect consists of the emission of electrons (electric current) that occurs when light falls on a metal surface under certain conditions.  

If the light is a stream of photons and each of them has energy, this energy is able to pull an electron out of the crystalline lattice of the metal and communicate, in addition, a kinetic energy.  

<u>This is what Einstein proposed: </u>

Light behaves like a stream of particles called photons with an energy  E:

E=\frac{hc}{\lambda} (1)  

So, the energy E of the incident photon must be equal to the sum of the Work function \Phi of the metal and the kinetic energy K of the photoelectron:  

E=\Phi+K (2)  

Where \Phi=6.94(10)^{-19} J is the minimum amount of energy required to induce the photoemission of electrons from the surface of Titanium metal.

Knowing this, let's begin with the answers:

<h3 /><h3>a)  Maximum possible kinetic energy of the emitted electrons (K)</h3>

From (1) we can know the energy of one photon of 233 nm light:

E=\frac{hc}{\lambda}

Where:

h=6.63(10)^{-34}J.s is the Planck constant  

\lambda=233 (10)^{-9} m is the wavelength

c=3 (10)^{8} m/s is the speed of light

E=\frac{(6.63(10)^{-34}J.s)(3 (10)^{8} m/s)}{3 (10)^{8} m/s} (3)

E=8.53(10)^{-19} J (4) This is the energy of one 233 nm photon

Substituting (4) in (2):

8.53(10)^{-19} J=6.94(10)^{-19} J+K (5)  

Finding K:

K=1.59(10)^{-19} J (5)  This is the maximum possible kinetic energy of the emitted electrons

<h3>b) Maximum number of electrons that can be freed by a burst of light whose total energy is 2 \mu J=2(10)^{-6} J</h3>

Since one photon of 233 nm is able to free at most one electron from the Titanium metal, we can calculate the following relation:

\frac{E_{burst}}{E}

Where E_{burst}=2(10)^{-6} J is the energy of the burst of light

Hence:

\frac{E_{burst}}{E}=\frac{2(10)^{-6} J}{8.53(10)^{-19} J}=2.34(10)^{12} electrons This is the maximum number of electrons that can be freed by the burst of light.

4 0
3 years ago
A ball rolls up a hill, going from a speed of 8.09 m/s to a speed of 5.87 m/s in 9.17 seconds. What is its acceleration?
PilotLPTM [1.2K]

Answer:

Explanation:

Comment

It's actually a deceleration. You should get a negative answer because the ball is slowing down.

Givens

vi = 8.09 m/s

vf = 5.87 m/s

t = 9.17

Formula

a = (vf  - vi) /t                     Substitute the givens into the formula

Solution

a = (5.87 - 8.09)/9.17

Answer

a = - 2.22 m/s^2

4 0
1 year ago
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