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Crank
3 years ago
12

If the pressure of a gas sample is quadrupled and the absolute temperature is doubled. True or False

Physics
1 answer:
Vanyuwa [196]3 years ago
6 0

The given statement"If the pressure of a gas sample is quadrupled and the absolute temperature is doubled" is false.

Answer: Option B

<u>Explanation:</u>

As we know the direct relationship between Pressure and Temperature by the Gay-Lussac’s Law,

                     P_{1} T_{1}=P_{2} T_{2}

From this, we get,

                     \frac{P_{1}}{T_{2}}=\frac{P_{2}}{T_{1}}

                     T_{2}=\frac{P_{1} T_{1}}{P_{2}}

So, according to given statement, we have P_{2} = 4 P_{1}

Then from the above expression, we can find out the value of T_{2} when pressure increased by 4 times of initial pressure as,

                     T_{2}=\frac{P_{1} T_{1}}{4 P_{1}}

Hence, we get,

                      T_{1}=4 T_{2}

Hence, from the above expression we can say that as we increase the pressure four times, the temperature does not get doubled. So, the given statement in the question is false.

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mariarad [96]

5m/s

100m

Explanation:

Average speed is sum of distance distance traveled in a given time by a body.

 Average speed= \frac{total distance covered}{time taken}

Distance = 20m

time = 4s

  Average speed = \frac{20}{4} = 5m/s

For the spaceship;

   Distance covered = speed x time

Speed = 50m/s

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learn more:

Average speed brainly.com/question/5063905

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2 years ago
A coyote can locate a sound source with good accuracy by comparing the arrival times of a sound wave at its two ears. Suppose a
il63 [147K]

Answer:

0.0000109261200583 s

0.0109261200583

Explanation:

d_2 = Distance from right ear = 3 m

s = Distance between ears = 15 cm

v = Speed of sound in air = 343 m/s

Distance between the left ear and the bird

d_1=\sqrt{s^2+d_2^2}\\\Rightarrow d_1=\sqrt{0.15^2+3^2}\\\Rightarrow d_1=3.00374765918\ m=3.004\ m

Time

t=\dfrac{Distance}{Speed}

Time difference would be

\Delta T=\dfrac{d_1}{v}-\dfrac{d_2}{v}\\\Rightarrow \Delta T=\dfrac{3.00374765918}{343}-\dfrac{3}{343}\\\Rightarrow \Delta T=0.0000109261200583\ s

The time difference is 0.0000109261200583 s

Time period is given by

T=\dfrac{1}{f}\\\Rightarrow T=\dfrac{1}{1000}\\\Rightarrow T=10^{-3}\ s

The ratio is

\dfrac{\Delta T}{T}=\dfrac{0.0000109261200583}{10^{-3}}\\\Rightarrow \dfrac{\Delta T}{T}=0.0109261200583

The ratio is 0.0109261200583

7 0
3 years ago
What is the wavelength of violet light that has a frequency of 7.5x10^14
Crank
Λ= V/f 
<span>but change it to represent the speed of light, c </span>
<span>λ= c/f </span>
<span>c = 3.00 x 10^8 m/s </span>
<span>Plug in your given info and solve for λ(wavelength) </span>
<span>λ= 3.00 x 10^8 m/s / 7.5 x 10^14 Hz
(3.00 x 10^8) / (7.5 x 10^14) = 300,000,000 / 750,000,000,000,000 = 0.0000004
Hope this helps :)
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