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Sedaia [141]
1 year ago
8

Use atomic properties to explain the reduction of a less active metal by a more active one:(b) in the molten state. Give a speci

fic example of each process.
Chemistry
1 answer:
Bad White [126]1 year ago
6 0

The reduction of a less active metal by a more active one is called metal displacement reactions. For example:

Fe + CuSO4 → FeSO4 + Cu

<h3>What is metal displacement reaction? </h3>

Displacement reactions is a reaction which includes a metal and the compound of a other metal. A more reactive metal will push or displace out a less reactive metal from its compound in this displacement reaction. The metal which is less reactive left uncombined after the reaction.

As we know that, electrons are the basis of the chemical reactions. If chemical compound or element A is more easily oxidized than B, then according to the terms of the activity series, the elements which are more easily oxidized can react with more chemicals, since they are able to act as a reducing agents for more chemicals.

Since, Metal ions are positively charged ions as they lose electrons. Some metals give up their electrons more readily than others and become more reactive.

Thus, we concluded that the reduction of a less active metal by a more active one is called metal displacement reactions. For example:

Fe + CuSO4 → FeSO4 + Cu

learn more about metal displacement reaction:

brainly.com/question/11777638

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The starting substances in a chemical reaction are called reactants - they are written on the left side of a chemical equation.
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3 years ago
1 loop in the primary coil and 8 loops in the secondary. If the secondary voltage is 120 V, what must be the primary voltage
Jet001 [13]

Answer:

V_{p} = 15 V

Explanation:

<u>Given the following data;</u>

Number of loops in primary coil, Np = 1 loop.

Number of loops in secondary coil, Ns = 8 loops

Voltage in secondary coil, Vs = 120V

To find the voltage in the primary coil, Vp;

Transformer ratio is given by the formula;

\frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}}

Making Vp the subject of formula;

V_{p} = \frac{N_{p}}{N_{s}} * V_{s}

Substituting into the equation, we have;

V_{p} = \frac{1}{8} * 120

V_{p} = \frac{120}{8}

V_{p} = 15 V

Therefore, the voltage in the primary coil, Vp is 15 Volts.

4 0
3 years ago
Which of the following is used in pencils?
Mamont248 [21]

Answer:

1st answer:  A. Graphite

2nd answer:  B.  Mercury

Explanation:

3 0
3 years ago
Read 2 more answers
If you have a 4.6 L of gas in a piston at a pressure of 1.2 atm and compress 2p the gas until its volume is 2.6 L, what will the
Nesterboy [21]

Answer:

2.12atm

Explanation:

Boyle's Law: P1V1 = P2V2

Manipulate to solve for unknown: P2 = P1V1/V2

Substitute values:  P2=(1.2atm)(4.6L)/2.6L

P2 = 2.1230769atm

Round to 3 sig figs to get 2.12atm

3 0
3 years ago
Acid strength in a series of h−a molecules increases with increasing size of
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Hello there!

The statement that Acid strength in a series of H-A molecules increases with increasing size of A is True.

When only the size is involved, increasing the size will increase the Acid strength because as size increases, the H-A bond will become weaker as the atoms will be farther apart. Acid strength is related to the ability to release H⁺ ions and a weaker H-A bond will release H⁺ more easily. 

Have a nice day!
8 0
3 years ago
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