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almond37 [142]
3 years ago
12

White light, which consists of all frequencies, forms which type of spectrum?

Chemistry
1 answer:
malfutka [58]3 years ago
5 0
Visible light spectrum.

The visible light spectrum is part of the electromagnetic radiation spectrum
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Calculate the mass (in g) of 2.1 x 1024 atoms of W.
Monica [59]
Atomic mass W = 183.84 u.m.a

183.84 g ----------- 6.02x10²⁴ atoms
?? g ---------------- 2.1x10²⁴ atoms

2.1x10²⁴ x 183.84 / 6.02x10²⁴ =

3.860x10²⁶ / 6.02x10²⁴ = 641.30 g

hope this helps!
4 0
3 years ago
17. D i don’t know if i’m writing it wrong or don’t know how to balance but ye
leva [86]

Answer:

2 KL + Pb(NO3)2 = 2 KNO3 + PbL2

Explanation:

KL + Pb(NO3)2 = KNO3 + PbL2 is unballanced equation, just balance from there :)

8 0
3 years ago
What is the empirical formula of a compound with a percent composition of 22.5% Phosphorous and 77.5% Chlorine?
sashaice [31]

Answer:

\boxed {\boxed {\sf PCl_3}}

Explanation:

We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.

We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.

  • 22.5 g P
  • 77.5 g Cl

Next, convert these masses to moles, using the molar masses found on the Periodic Table.

  • P: 30.974 g/mol
  • Cl: 35.45 g/mol

Use the molar masses as ratios and multiply by the number of grams. 22.5 \ g \ P  * \frac {1 \ mol \ P }{30.974 \ g \ P}= \frac {22.5 \ mol \ P }{ 30.974} = 0.7264157035 \ mol \ P

77.5 \ g \ Cl  * \frac {1 \ mol \ Cl }{35.45 \ g \ Cl}= \frac {77.5 \ mol \ Cl }{ 35.45} \ =2.186177715 \ mol \ Cl

Divide both of the moles by the smallest number of moles to find the mole ratio.

\frac {0.7264157035} {0.7264157035} = 1

\frac {2.186177715}{0.7264157035}=3.009540824 \approx 3

The mole ratio is about 1 P: 3 Cl, so the empirical formula is written as:<u> PCl₃</u>

4 0
3 years ago
If I add water to 100mL of a 0.15M NaOH solution until the final volume is 150mL, what will the molarity of the diluted solution
Mars2501 [29]

Answer : A

0,15 moles of NaOH -------in-------1000ml

x moles of NaOH ---------in-------100ml

x= 0,015 moles of NaOH

final volume =150ml

0,015 moles of NaOH -------in------150ml

x moles of NaOH ------in--------1000ml

x= 0,1 moles of NaOH

7 0
3 years ago
Hydrogen iodide can decompose into hydrogen and iodine gases. 2 HI(g) H2(g) + 12(g) Kp for the reaction is 0.016. If 0.350 atm o
solniwko [45]

Answer : The total pressure at equilibrium is 0.350 atm

Solution :  Given,

Initial pressure of HI = 0.350 bar

K_p = 0.016

The given equilibrium reaction is,

                             2HI(g)\rightleftharpoons H_2(g)+I_2(g)

Initially                  0.350           0       0

At equilibrium       (0.350-2x)    x       x

The total pressure at equilibrium = (0.350-2x)+x+x=0.350-2x+2x=0.350atm

Thus, the total pressure at equilibrium is 0.350 atm

4 0
3 years ago
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