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maria [59]
3 years ago
12

The formula for a compound of Li₊ ions and Br_ ions is written LiBr. Why can't it be written Li₂Br? Why isn't it written BrLi?

Chemistry
2 answers:
Ahat [919]3 years ago
7 0

Answer: Group 1 elements have an oxidation charge of +1. They are alkali metals and Li is one of them. For Br it is a halogen and in group 7 so it has an oxidation of -1. If we do the criss cross rule it will ha Li+¹ Br-¹. Put each charges interchangeably on each elements. So the charge of Li will be the subscript of Br and vice versa. Since both have the same charge they will cancel out on the final equation of the compound.

Explanation:

bogdanovich [222]3 years ago
5 0

Answer:

.

Explanation:

Lithium is in the first column of the periodic table, so it will have 1 valence electron.

Bromine is in the seventh column of the periodic table, so it will have seven valence electrons.

They must combine in a way to reach 8.

When combining elements to form compounds, the "crisscross method" is used. Above Li would be a charge of +1, and above Br would be a charge of -1.

Cross the 1 from the top of Li to the bottom of Br, and so there is 1 Br.

Cross the 1 from the top of Br to the bottom of Li, and so there is 1 Li.

It is not written BrLi because chemists decided to order them the other way. Technically speaking, it isn't wrong, but the positive charge is normally put on the left and the negative charge is normally put on the right.

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Explanation:

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8 0
3 years ago
In an experiment, potassium chlorate decomposed according to the following chemical equation.
Arada [10]

Answer:  

(240 × 3 × 31.998)/(122.5 × 2)   g

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:          122.5                31.998

               2KClO₃ ⟶ 2KCl + 3O₂

Mass/g:     240  

Mass of O₂ = 240 g KClO₃ × (1 mol KClO₃/122.5 g KClO₃) × (3 mol O₂/2 mol KClO₃)  × (31.998 g O₂/1 mol O₂) = 94.0 g O₂

Mass of O₂= (240 × 3 × 31.998)/(2 × 122.5) = 94.0 g O₂


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Explanation:

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