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3 years ago

Which type of galaxy has the most active star formation?

Physics

2 answers:

UkoKoshka [18]3 years ago

8 0

That answer is spiral galaxies

asambeis [7]3 years ago

4 0

A IS THE ANSWER-

- Audrey -

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What adaptation in frogs enables them to swim

Flauer [41]

Answer:

Most of the frogs have webbed feet which helps them swim. The thin skin between the toes helps them to push through the water. The frog's feet is webbed ,So they can easily swim.. The skin between toes are flexible soo they can freely push and pull it

Explanation:

6 0

4 years ago

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Radon-222 ( 222/86 Rn) is a radioactive gas with a half-life of 3.82 days. A gas sample contains 4.1 e 8 radon atoms initially.

kow [346]

Answer :

(a) The number of radon atoms will remain after 12 days is, $4.67\times 10^7$

(b) The number of radon nuclei have decayed by this time will be, $3.6\times 10^8$

Explanation :

For part (a) :

Half-life = 3.82 days

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{3.82\text{ days}}$

$k=1.81\times 10^{-1}\text{ days}^{-1}$

Now we have to calculate the number of radon atoms will remain after 12 days.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.81\times 10^{-1}\text{ days}^{-1}$

t = time passed by the sample = 12 days

a = initially number of radon atoms = $4.1\times 10^8$

a - x = number of radon atoms left = ?

Now put all the given values in above equation, we get

$12=\frac{2.303}{1.81\times 10^{-1}}\log\frac{4.1\times 10^8}{a-x}$

$a-x=4.67\times 10^7$

Thus, the number of radon atoms will remain after 12 days is, $4.67\times 10^7$

For part (b) :

Now we have to calculate the number of radon nuclei will have decayed by this time.

The number of radon nuclei have decayed = Initial number of radon atoms - Number of radon atoms left

The number of radon nuclei have decayed = $(4.1\times 10^8)-(4.67\times 10^7)$

The number of radon nuclei have decayed = $3.6\times 10^8$

Thus, the number of radon nuclei have decayed by this time will be, $3.6\times 10^8$

5 0

3 years ago

A typical rechargeable deep-cycle battery for an electric trolling motor (fishing boat) delivers 10A of current at a voltage of

Oksi-84 [34.3K]

Answer:

a) 360 kQ

b) 4.32 MJ

c) 1200 W-h

Explanation:

a) The definition of the current is.

$I= \frac{Q}{t}$

having a count that 10 hours = 36.000 s

$Q = I*t$

$Q = 36000*10 = 360.000 [Q]$

b) The definition of the Energy in power terms is.

$E = \int\limits^{t}_{0} {P} \, dt$

and the definition of power is:

$P = V*I = 12 * 10 = 120 [W]$

replacing in the energy formula.

$E = \int\limits^{36.000}_{0} {120} \, dt$

solving the integral, have into account that t is in seconds.

$E=P*t=120*36000=4.320.000=4.32 [MJ]$

c) The energy in W-h, we can find it multiplying power by hours

$E = P*t =120*10 = 1200 W-h$ .

3 0

3 years ago

Which statement best compares potential and kinetic energy?

Eddi Din [679]

Answer:

I think option 1st is correct

lf it is wrong I apologise

HAVE A NICE DAY

8 0

3 years ago

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How does energy limit the number of trophic levels in an energy pyramid?

nadya68 [22]

Answer: The amount of energy at each trophic level decreases as it moves through an ecosystem. As little as 10 percent of the energy at any trophic level is transferred to the next level; the rest is lost largely through metabolic processes as heat.

Explanation:

6 0

3 years ago

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