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3 years ago

Which type of galaxy has the most active star formation?

Physics

2 answers:

UkoKoshka [18]3 years ago

8 0

That answer is spiral galaxies

asambeis [7]3 years ago

4 0

A IS THE ANSWER-

- <em>Audrey -</em>

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Neglecting air resistance, if a ball is thrown 4.5 m/s horizontally from a 94-m cliff, how far has the ball fallen after 2.7 s?

kati45 [8]

Check the attached file for the answer.

6 0

4 years ago

An iron wire has length 8.0m and a diameter 0.50mm. The sir has a resistance R.

Rudik [331]

The re<span>sistance of the second wire is 16 R.
where R is the resistance of the first wire.

R = </span>ρ $\frac{l}{A}$
where l = length of the wire
A = area of the wire
A = $\pi r^{2}$ where, r = $\frac{diameter of wire}{2}$

Thus, on finding the ratio of resistance of the two wires, we get,

$\frac{R1}{R2} = \frac{l1A2}{l2A1}$

here, R1 = R
l1 = 8m
l2 = 2m
A1=π $0.25^{2}$
A1=π $0.50^{2}$

we get. R2 = 16R

7 0

4 years ago

What would happen if you touched an object that is the same temperature as your hand? Would any heat transfer happen? Explain yo

ICE Princess25 [194]

Answer:

It actually depends.

Explanation:

in the case of a metal ur hand will absorb the heat (but it depends on the temperature, this ans favours hot and cold but not neutral or room temperature), in the case of human to human I think no heat transfer will take place, in the case of liquids(for hot temperature ,it would even for cold but not room).

It basically involves application

4 0

3 years ago

A turntable that is initially at rest is set in motion with a constant angular acceleration α. What is the magnitude of the angu

bekas [8.4K]

Explanation:

If the turntable starts from rest and is set in motion with a constant angular acceleration α. Let $\omega$ is the angular velocity of the turntable. We know that the rate of change of angular velocity is called the angular acceleration of an object. Its formula is given by :

$\alpha =\dfrac{\omega_f-\omega_i}{t}$

$\alpha =\dfrac{\omega-0}{t}$

$\alpha =\dfrac{\omega}{t}$

$t=\dfrac{\omega}{\alpha }$ ............(1)

Using second equation of kinematics as :

$\theta=\omega_i t+\dfrac{1}{2}\alpha t^2$

$\theta=\dfrac{1}{2}\alpha t^2$

Using equation (1) in above equation

$\theta=\dfrac{1}{2}\times \dfrac{\omega^2}{\alpha }$

In one revolution, $\theta=4\pi$ (in 2 revolutions)

$4\pi =\dfrac{1}{2}\times \dfrac{\omega^2}{\alpha }$

$\omega=\sqrt{8\pi \alpha}$

$\omega=2\sqrt{2\pi \alpha}$

Hence, this is the required solution.

6 0

4 years ago

Read 2 more answers

Measurements of the amount of dna per nucleus were taken on a large number of cells from a growing fungus. The measured dna leve

mamaluj [8]

Answer:

It's on the G2 stage

Explanation:

During the cell cycle, DNA levels range from a minimum during G1 to a maximum after S phase but before cytokinesis. Since the cell in question has more than the minimum but equally to the maximum per nucleus, it must be in the final phase, which is G2.

7 0

3 years ago