Does anyone understand Hybrid Orbitals?
1 answer:
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<u>Answer:</u> The enthalpy of the reaction is 269.4 kJ/mol
<u>Explanation:</u>
To calculate the heat absorbed by the calorimeter, we use the equation:
where,
q = heat absorbed
c = heat capacity of calorimeter = 675 J/°C
= change in temperature =
Putting values in above equation, we get:
To calculate the heat absorbed by water, we use the equation:
where,
q = heat absorbed
m = mass of water = 925 g
c = heat capacity of water = 4.186 J/g°C
= change in temperature =
Putting values in above equation, we get:
Total heat absorbed =
Total heat absorbed =
To calculate the enthalpy change of the reaction, we use the equation:
where,
q = amount of heat absorbed = 134.7 kJ
n = number of moles of hydrocarbon = 0.500 moles
= enthalpy change of the reaction
Putting values in above equation, we get:
Hence, the enthalpy of the reaction is 269.4 kJ/mol