The question is incomplete, the complete question is;
With all of this data in hand, we can now set up our reaction. To begin we are going to use 0.7 g of (35)-2.2-dibromo-3,4-dimethylpentane. Question #7: Using the molecular weight (258 g/mol) determine the amount of mmol of (3S)-2,2,- dibromo-3,4-dimethylpentane required. Round to the tenths place
Answer:
2.70 mmols
Explanation:
Given that;
Mass of (3S)-2,2,- dibromo-3,4-dimethylpentane = 0.7 g
Molar mass of (3S)-2,2,- dibromo-3,4-dimethylpentane = 258 g/mol
From,
Number of moles = mass/molar mass
Number of moles of (3S)-2,2,- dibromo-3,4-dimethylpentane = 0.7g/258 g/mol = 2.7 ×10^-3 moles
Therefore;
Number of moles of (3S)-2,2,- dibromo-3,4-dimethylpentane = 2.70 mmols
