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notka56 [123]
3 years ago
15

The levels of organizations in multicellular organisms are shown below, but they are not in the correct order. Arrange the level

s of organization in order from simplest to most complex.
Chemistry
1 answer:
artcher [175]3 years ago
7 0

The question is incomplete, the complete question is;

The levels of organizations in multicellular organisms are shown below, but they are not in the correct order. Arrange the levels of organization in order from simplest to most complex. tissues organs whole organisms organ systems

Answer:

tissues --> organs --> organ system --> whole organisms

Explanation:

The levels of organizations in multicellular organisms refers to the increasing complexity of the components of the organism.

A tissue is an aggregation of cells hence it is the lowest level of organization here.

Organs are an aggregation of tissues, this is the next higher level of organization.

Organ systems are an aggregation of organs, this is the next higher level of organization.

Whole organisms are an aggregation of organ systems. This is the highest level of organization.

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Answer: Chemical X H3 and f1

Explanation:

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Magnesium hydroxide is only very slightly soluble in water. The reaction by which it goes into solution is: Mg(OH) 2 (s) rightle
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Answer:

there will a definite decrease in solute solution

Explanation:

acid reaction acting upon negative charge.

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3 years ago
Answer number 3 plzz
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Answer:

energy

Explanation:

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3 years ago
A metal X from two oxide A and B .3.oogm of A and B contain 0.72 and 1.16g of oxygen respectively.calculate the maases of metal
devlian [24]

Answer:

Explanation:

Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.

Metal X can form 2 oxides (A and B).

A + B = 3g

The mass of oxygen in A is 0.72g and the mass of oxygen in B is 1.16g.

The mass of metal X in the two oxides will be the same because it's the same metal.

Thus, we represent the mass of the metal in the two oxides as 2X.

2X + 0.72 + 1.16 = 3

2X + 1.88 = 3

2X = 3 - 1.88

2X = 1.12

X = 0.56

<u>Thus, 0.56 g of the metal combines with 0.72g of oxygen in A and 1.16 g of oxygen in B.</u>

Thus, mass of metal (X) in 1g of oxygen in A is

0.56g ⇒ 0.72g

X ⇒ 1

X = 1 × 0.56/0.72

X = 0.78 g

Hence, 0.78g of the metal will combine with 1g of oxygen for A

Also, mass of metal (X) in 1g of oxygen in B is

0.56g ⇒ 1.16g

X ⇒ 1g

X = 1×0.56/1.16

X = 0.48 g

Thus, 0.48g of the metal will combine with 1g of oxygen for B

6 0
3 years ago
How many moles are there in 3.612 x 1024 formula units of Na2SO4?
vitfil [10]

Answer:

<h3>Theanswer is 6 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.612 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>6 moles</h3>

Hope this helps you

5 0
3 years ago
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