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velikii [3]
2 years ago
15

Please explain or show work -2x + 3y = 12 2x + 3y = 0

Mathematics
1 answer:
photoshop1234 [79]2 years ago
4 0

Answer:

See below

Step-by-step explanation:

This is a system of equations. That means you are trying to find the point that makes both lines true at the same time.

To do this you have to solve for one variable at a time. Luckily, these equations already have one variable that will cancel. If you add 2x and -2x, you get 0. I'm going to line these up like a vertical math problem to show you how it works.

-2x + 3y = 12

2x +3y = 0                    Add together

-------------------

0x + 6y = 12                Simplify by removing the 0x

6y =12                        Divide both sides by 6 to solve for y

y = 2

Plug 2 in for y in one of the original equations.

2x + 3(2) = 0

2x + 6 = 0                   Subtract 6 from both sides

2x = -6                        Divide by 2 to solve for x

x = -3

The point that makes both lines true is (-3,2). This is where the lines intersect.

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Answer:

Assuming that they will both tip, it will be a $5.63 tip.

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3 years ago
Nelson and 3 friends rent a bounce house. It cost $50 for setup and $30 per hour. If they all split the cost, how much will each
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Answer:

A: 50

Step-by-step explanation:

because its 50$ for setup and 30 each hour for 5 hours. so 30x5=150 +50 = 200÷ nelson and 3 friends =50$ each

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4 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
3 years ago
John sold one more than twice as many candy bars as Linda sold. If together they sold 43 candy bars, how many did John sell?
finlep [7]

Answer:

Step-by-step explanation:

Linda sold 14

John sold 29 which is 14 two times plus one

29+14=43

5 0
3 years ago
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