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forsale [732]
4 years ago
15

Difference in solubility products and molar solubility?

Chemistry
1 answer:
klasskru [66]4 years ago
3 0
I dont know kid, gotta ask someone else.
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Explain how dalton's theory of the atom and the conservation of mass are related
Scorpion4ik [409]

Answer:

Dalton's atomic theory states that atoms may be mixed in certain rations to produce compounds, while the law of conservation of mass states that the mass of reactants equals the mass of products. They are related because in the production of compounds, Dalton made it clear that mass can neither be destroyed or created, which supports the conservation of mass law.

Explanation:^^^

Hoped it helped...

8 0
3 years ago
Consider the statement: “The temperature of the land is an important factor for the ripening of oranges, because it affects the
Alexxx [7]
Physical Properties<span>: </span>Physical properties<span> can be observed or measured without changing the composition of matter. </span>Physical properties<span> are used to observe and describe matter. so physical changes are the change in temperature of the land and the evaporation of water and change humidity of the air. chemical change is the ripening of the orange</span>
7 0
3 years ago
Calculate the quantity of energy released when 783 g of steam condenses.<br><br> (show work)
Angelina_Jolie [31]

Answer:

firstark as brainliest

Explanation:

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7 0
3 years ago
Pcl5 exist but ncl5 does not.why?
jeyben [28]
N is as electronegative as Cl is. So Cl doesnt react with O, N
6 0
3 years ago
An ideal gas sealed in a rigid 4.86-L cylinder, initially at pressure Pi=10.90 atm, is cooled until the pressure in the cylinder
seraphim [82]

Answer:

\Delta H=-11897J

Explanation:

Hello,

In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:

\Delta H=\Delta U+V\Delta P

Whereas the change in the internal energy is computed by:

\Delta U=nCv\Delta T

So we compute the initial and final temperatures for one mole of the ideal gas:

T_1= \frac{P_1V}{nR}=\frac{10.90atm*4.86L}{0.082*n}=\frac{646.02K  }{n} \\\\T_2= \frac{P_2V}{nR}=\frac{1.24atm*4.86L}{0.082*n}=\frac{73.49K  }{n}

Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:

\Delta U=1mol*\frac{3}{2} (8.314\frac{J}{mol*K} )*(73.49K-646.02K )=-7140J

Then, the volume-pressure product in Joules:

V\Delta P=4.86L*\frac{1m^3}{1000L} *(1.24atm-10.90atm)*\frac{101325Pa}{1atm} \\\\V\Delta P=-4756.96J

Finally, the change in the enthalpy for the process:

\Delta H=-7140J-4757J\\\\\Delta H=-11897J

Best regards.

7 0
4 years ago
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