Answer:
E) Br Br
Explanation:
Covalent bond -
Covalent bond is the bond which is formed with the sharing of the electrons between the two atoms which are taking part in the bond. It is generally formed between the atoms with similar electronegativity values.
It is the bond which is generally occurs within non metals as they share electrons to complete their octet.
The difference in the electronegativity values of the atoms involving in a covalent bond must not exceed the value of 1.7 .
A covalent bond to be non polar in nature , then the atoms need to have almost similar electronegativity , so that they won't split into partial negative and partial positive charge .
Hence , from the given options of the question ,
E) Br Br , both the atoms are same , hence same electronegativity , therefore are non - polar in nature .
The primary reason for this was that Mendeleev
didn't know that atomic numbers actually existed. Atomic numbers
were only discovered a period after Mendeleev's time. The use of X-rays made it
possible to find the atomic number, and those had not been discovered yet. <span>
<span>The periodic table was then arranged in 1913 by Henry Moseley
in an arrangement according to atomic number.</span></span>
Answer: I am confident the answer is B
Explanation:
forgive me if im wrong
F₂ + 2 NaI → 2 NaF + I₂
<span>It is given that F₂ is light yellow / colorless in hydrocarbon solvent. The student combines Fluorine water with NaI in water. Then student adds pentane in the mixture of F₂ and NaI. After dissolution, solution was observed and a colorless pentane layer was seen. Alkanes are unreactive in nature. The C-H bond in alkane is difficult to break. whereas, F₂ is very reactive and reacts vigorously with alkanes in presence of light by free radical mechanism.It is given that the color of the solution is nearly colorless. F₂ when present in hydrocarbon solvent is light yellow/ colorless/ nearly colorless. Hence, F₂ is not reacting with hydrocarbon and there is no reaction taking place (No F</span>₂ is present<span>)</span>