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Veseljchak [2.6K]
2 years ago
10

Which is always going to be the highest ionization energy?

Chemistry
1 answer:
Law Incorporation [45]2 years ago
4 0

Answer: I think it's B.

Explanation:

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A student asks a class the following question, “Polyethylene has a relatively short formula (C2H4) while nylon has a long formul
Verdich [7]

Answer:

ok

Explanation:

6 0
3 years ago
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5. A 25 kg object travels a distance of 90 m in 30 s. Find the momentum
xz_007 [3.2K]

Answer:

★ v = d/t

★ v = 90/30

★ v =3

<u>Acc</u><u> </u><u>to</u><u> </u><u>question</u>

★ momentum = mass * velocity

★ m = 25×3

★ m = 75kgm/s

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3 years ago
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A 0.0200 gram piece of unknown alkaline earth metal, M, is reacted with excess 0.500 M H 2 SO 4 , and the hydrogen gas produced
Rama09 [41]

Answer:

0.981atm

Explanation:

According ot Dalton's law total pressure of a mixture of non-reactive gas is equal to sum of partial pressures of individual gases.

total pressure= 1.01at

Number of gases=2

Gases: water vapor and hydrogen

partial pressure of water vapor= 0.029atm

1.01= partial pressure of water vapor+ partial pressure of hydrogen

1.01= 0.029 + partial pressure of hydrogen

partial pressure of hydrogen = 0.981atm

6 0
3 years ago
In h2o, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a
Murrr4er [49]
The hydrogen and oxygen<span> atoms from H</span>₂O are <span>bonded together through covalent </span>bonding. 
3 0
3 years ago
How much heat will be absorbed by a 26.3 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°
kotykmax [81]

Answer:

\boxed {\boxed {\sf 1076.196 \ Joules}}

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

q=mc\Delta T

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

  • The change in temperature is the difference between the initial temperature to the final temperature.
  • The temperature changes <em>from</em> 23.0°C <em>to</em> 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
  • ΔT= final temperature - initial temperature
  • ΔT= 67°C - 23°C
  • ΔT= 44°C

Now we know all the values.

  • m= 26.3 g
  • c= 0.930 J/g °C
  • ΔT= 44°C

Substitute the values into the formula.

q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)

Multiply the first two numbers together. The units of grams cancel.

q= 24.459 \ J/ \textdegree C \times 44 \textdegree C

Multiply again. This time, the units of degrees Celsius cancel.

q=1076.196 \ J

<u>1076.196 Joules</u> of heat will be absorbed by the piece of aluminum.

4 0
3 years ago
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