A) divide by 100. A meter is 100 centimeters so that’s how you can tell
It is the nimbostratus cloud.
Answer:
Ethoxy ethen. This compund is the functional group of ethar ( R-O-R )
Explanation:
The solubility equilibrium of PbCl
:
![K_{sp}=[Pb^{2+}][Cl^{-}]^{2}](https://tex.z-dn.net/?f=%20K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D%20%20%20)
![[Cl^{-}] = 2.88 * 10^{-2} M](https://tex.z-dn.net/?f=%20%5BCl%5E%7B-%7D%5D%20%3D%202.88%20%2A%2010%5E%7B-2%7D%20M%20)
![[Pb^{2+}]=\frac{[Cl^{-}]}{2} = \frac{2.88 * 10^{-2}}{2}=1.44 *10^{-2}](https://tex.z-dn.net/?f=%20%5BPb%5E%7B2%2B%7D%5D%3D%5Cfrac%7B%5BCl%5E%7B-%7D%5D%7D%7B2%7D%20%3D%20%5Cfrac%7B2.88%20%2A%2010%5E%7B-2%7D%7D%7B2%7D%3D1.44%20%2A10%5E%7B-2%7D%20%20%20%20)
= 
= 
So, the corrected solubility product will be
Answer:
The correct answer is 0.67 g H₂
Explanation:
Isopropyl alcohol (C₃H₇OH) can decompose to give acetone (C₂H₆OH) and hydrogen gas (H₂) according to the following chemical equation:
C₃H₇OH (g) ⇒ C₂H₆CO(g) + H₂(g)
We can calculate the initial mass of isopropyl alcohol from the density and volume data:
density = m/V = 0.785 g/mL
⇒ m = density x V = 0.785 g/mL x 25.6 mL = 20.096 g C₃H₇OH
According to the chemical equation 1 mol of C₃H₇OH gives 1 mol H₂. The molar mass of C₃H₇OH is:
molar mass C₃H₇OH = (12 g/mol x 3) + (1 g/mol x 7) + 16 g/mol + 1 g/mol = 60 g/mol
molar mass H₂ = 1 g/mol x 2 = 2 g/mol
So, we obtain: 2 g H₂ from 60 g C₃H₇OH. We multiply this stoichiometric ratio (2 g H₂/60 g C₃H₇OH) by the initial mass of C₃H₇OH to obtain the mass of H₂ is formed:
20.096 g C₃H₇OH x (2 g H₂/60 g C₃H₇OH) = 0.6698 g ≅ 0.67 g H₂
