Answer is: empirical formula for compound is C₂H₆O.
m(CO₂) = 1,6003 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 1,6003 g ÷ 44 g/mol.
n(CO₂) = 0,0364 mol.
n(CO₂) = n(C).
m(C) = 0,0364 mol · 12 g/mol = 0,4368 g.
m(H₂O) = 0,9827 g.
n(H₂O) = 0,9827 g ÷ 18 g/mol.
n(H₂O) = 0,0546 mol.
n(H) = 2 · n(H₂O) = 0,1092 mol.
m(H) = 0,1092 mol · 1 g/mol = 0,1092 g.
m(O) = 0,8376 g - 0,4368 g - 0,1092 g = 0,2916 g.
n(O) = 0,2916 g ÷ 16 g/mol = 0,0182 mol.
n(C) : n(H) : n(O) = 0,0364 mol : 0,1092 mol : 0,0182 mol.
n(C) : n(H) : n(O) = 2 : 6 : 1.
<span>Zn⁰(s) + CuSO4(aq) --> Zn²⁺SO4²⁻(aq) + Cu(s)
</span>Zn⁰ --- in free elements oxidation number is 0.
Zn²⁺SO4²⁻ ---- ionic compound , it has ion Zn²⁺, so oxidation number here is +2.
<span>The oxidation number of Zn changes from 0 to +2.</span>
Answer:
The correct option is;
C. Two in the first energy level, six in the second energy level
Explanation:
The electrons in an atom are arrange in orbital shells which are situated at different levels within the structure of the, depending on the energy of the electron. Electrons with the least amount of energy are found in the shell closest to the nucleus of the atom which is the first energy level
The maximum number of electrons that can be found in a given an energy level is obtained with the following formula;
The number of electron = 2 × n²
Where;
n = The number of the different energy level
Therefore;
The maximum number of electrons in the first energy where n = 1 is given as follows;
The number of electron = 2 × 1² = 2 electrons
The maximum number of electrons in the second energy level where n = 2 is given as follows;
The number of electron = 2 × 2² = 8 electrons
Given that there are only 8 electrons in the atom, we therefore have, 2 electrons in the first energy level and the remaining 8 - 2 = 6 electrons in the second energy level.
